PIc 16f1527 Ic uart problem

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rparthiban69

New Member

• Feb 19, 2013

• #1

I need PIC16f1527 UART sample code.


How to declare BAUDxCON,TX1STA and RC1STA bits,


BAUD1CONbits.BRG16=0;
BAUD1CONbits.ABDOVF=0;
BAUD1CONbits.RCIDL=0;
BAUD1CONbits.SCKP=0;
BAUD1CONbits.WUE=0;
BAUD1CONbits.ABDEN=1;
TX1STAbits.SYNC = 0; //
TX1STAbits.SYNC = 0; /* asynchronous */
TX1STAbits.SENDB= 0;
RC1STAbits.SPEN = 1; /* enable serial port pins */
RC1STAbits.CREN = 1; /* enable reception */ RC1STAbits.SREN = 0; /* no effect */
PIE1bits.TX1IE = 0; /* disable tx interrupts */
PIE1bits.RC1IE = 0; /* disable rx interrupts */
TX1STAbits.TX9 = 0; /* 8- or 9-bit transmission */
RC1STAbits.RX9 = 0; /* 8- or 9-bit reception */
TX1STAbits.TXEN = 1; /* enable the transmitter */

 

Ian Rogers

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• Feb 19, 2013

• #2

What compiler are you using?.... Check you documentation as there will most likely be a library with it done for you!!!

 

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rparthiban69

New Member

• Feb 19, 2013

• #3

I am using Hitech c compiler...

 

Ian Rogers

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• Feb 20, 2013

• #4

Thought so... Navigate to the.. "Program files \ Hi-tech software \ PICC \ 9.83 \ samples \ USART \"

Here you will find a template that will get you started....

It might be useful to you to browse through the pic16f1527.h fil.. All the declarations are in there..

 

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rparthiban69

New Member

• Feb 20, 2013

• #5

thanks.

PIC 16f1527 ic have a two uarts. i need use uart1? how to seperate it?

 

Ian Rogers

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• Feb 20, 2013

• #6

Just re-write it to suit.... What's your FOSC? ( this is to find out if you need SPBRGH, This is the only difference.. )

If not the USART header still enumerates correctly ( in other words it defaults to USART1 )..

 

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rparthiban69

New Member

• Feb 20, 2013

• #7

FOSC 20MHZ, Baud rate 56700.

 

Ian Rogers

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• Feb 21, 2013

• #8

Then you will be fine.... Just include the line "SPBRGH = 0;" in the initUART(); and it should be fine...

 

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rparthiban69

New Member

• Feb 21, 2013

• #9

Ian Rogers said:

Then you will be fine.... Just include the line "SPBRGH = 0;" in the initUART(); and it should be fine...

Click to expand...

have doubt in UART baudrate formula

SYNC=BRGH=BRG16=0, formula FOSC/[64(n+1)]
SYNC=BRG16=0,BRGH=1, formula FOSC/[16(n+1)]

in my program SYNC=0;BRG16=1;BRGH=1;

can i use this formula
SYNC=0;BRGH=BRG16=1, formula FOSC/[4(n+1)]

 

Ian Rogers

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• Feb 21, 2013

• #10

Yes! as long as you set the BRG16 bit...

 

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rparthiban69

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• Feb 21, 2013

• #11

Ya i am sending 35 00 11 00 00 00 0A 18 0B 00 00 00 00 00 00 00 01 CA this much data....

 

Ian Rogers

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• Feb 21, 2013

• #12

rparthiban69 said:

Ya i am sending 35 00 11 00 00 00 0A 18 0B 00 00 00 00 00 00 00 01 CA this much data....

Click to expand...

OK? And!

 

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rparthiban69

New Member

• Feb 21, 2013

• #13

Ok....

Check this link https://www.edaboard.com/thread278797.html#post1201252

My program is correct or not?