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As RadioRon stated it's the average current not the peak. Perhaps you don't understand average current. It would be the amount of the peak current times the transient time divided by the time between transients. Since the transient time is generally much shorter than the time between peaks, the average current is much less than the peak current.Thanks.
That is what i too thought.But the buck converter needs to replenish the bypass capacitor right.Bypass capacitor is connected directly to the Vcc(buck converter output).So once the bypass capacitor supplies the transient current of the cmos counter,buck converter needs to replenish the bypass capacitor.Wont that mean buck converter needs to supply the current equal to the amount of the peak current (transient current
That doesn't happen because the converter can't respond to the fast transients. Most voltage regulators and converters have a relatively low frequency response (in the kHz region), so they just respond to regulate the low frequency voltage level changes and ignore the fast transients. They supply an average current to keep the cap charged to the average voltage level. The cap voltage will thus show a small high frequency sawtooth type ripple as the transient currents are charged and discharged but that's ignored by the regulator.say the peak transient current is 50mA and the average current is 3mA for a counter...i have selected a buck for say 45 mA...i have put a bypass capacitor of 0.1uF...Now during transient say ,the bypass capacitor supplies the current of 50 mA..now bypass capacitor will loose charge and it is directly connected to buck converter output...Now what will be the current that flows through the bypass capacitor from the buck converter for recharging the capacitor...wont it be very high value which buck converter cannot supply...