Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Need help with schematic, not understanding

Status
Not open for further replies.

integralx2

New Member
What is that switch between AC to DC mean ? What kind of part is it ?
 

Attachments

  • ecggask.png
    ecggask.png
    20 KB · Views: 194
With the switch in the DC position there will be an offset voltage at the output of the INA321. In the AC position the offset voltage is 0 volt.
 
The DC position couples both the AC and DC portion of the signal, it's DC coupled. In the AC position only the AC portion is coupled. It connects a feedback integrator which acts the same as if there were a high-pass filter coupling capacitor in series with the output (there's a notation on the schematic which tells you that the HPF -3dB point is 0.5Hz). The advantage of the integrator is that you can use a high resistor to generate a low-frequency rolloff, which may not be practical with the usual LPF in series with the output.
 
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top