i write a program code that will run when a choice is made ;
Compiler: mikroC
please choose:
1.) start
2.) stop
when '1' is chosen, it will display 'hello' continuously. If any other button is press, the program will go back to the menu selection untill '1' is pressed to start..
The 'hello' must run continuously.. the problem is once '1' is pressed, i cant press '2' to stop it... so now, i want to interrupt it once its started so that i can stop the program.. i've tried using the interrupt but to no avail..
i need help !! any1 check my codes pleasee!! (sorry, i'm new to C language and PIC. this is my 1st attempt)
thank you in advance~
here is the codes without interrupt
codes with the interrupt
i run the codes( with interrupt)..
but why does the programme displays the menu selection continuously, instead of waiting for my input ( i.e. : usart_read)
i wanted the program to wait for my input, then go through the main program loop ( attention: the 'read()' must run continuosly !! )
and the program has to stop when i press '2'..
please help!!
Compiler: mikroC
please choose:
1.) start
2.) stop
when '1' is chosen, it will display 'hello' continuously. If any other button is press, the program will go back to the menu selection untill '1' is pressed to start..
The 'hello' must run continuously.. the problem is once '1' is pressed, i cant press '2' to stop it... so now, i want to interrupt it once its started so that i can stop the program.. i've tried using the interrupt but to no avail..
i need help !! any1 check my codes pleasee!! (sorry, i'm new to C language and PIC. this is my 1st attempt)
thank you in advance~
here is the codes without interrupt
Code:
unsigned int i;
void usart_str_write(char* string)
{
while ((*string) != '\0'){
//while (strlen(string)){
Usart_Write((char) (*string));
++string;
}
Usart_Write('\r'); // add a new line to every string
}
unsigned int read()
{
while(1)
{
usart_str_write("hello");
}
return (0);
}
void main()
{
ADCON1 = 0x00; // to configure analog inputs and Vref=vdd
TRISA = 0xFF; // PORTA is input ( to read adc input)
USART_Init(9600);
usart_str_write("please choose:");
usart_str_write("1.) start");
usart_str_write("2.) stop");
do{ if (Usart_Data_Ready()) // If data is received
{
i = Usart_Read();
if ( i == '1')
{
usart_str_write("->execute");
USART_Write(0x0D);
read();
}
else
{
usart_str_write("please choose:");
usart_str_write("1.) start");
usart_str_write("2.) stop");
}
}
}
while(1);
}codes with the interrupt
Code:
unsigned int i;
void usart_str_write(char* string)
{
while ((*string) != '\0'){
//while (strlen(string)){
Usart_Write((char) (*string));
++string;
}
Usart_Write('\r'); // add a new line to every string
}
unsigned int read()
{
while(1)
{
usart_str_write("hello");
}
return (0);
}
void interrupt()
{
if (PIR1.RCIF=1)
{
if (Usart_Data_Ready())
{
i = Usart_Read();
}
}
PIR1.RCIF=0;
}
void main()
{
ADCON1 = 0x00; // to configure analog inputs and Vref=vdd
TRISA = 0xFF; // PORTA is input ( to read adc input)
USART_Init(9600);
INTCON.GIE=1;
INTCON.PEIE=1;
PIE1.RCIE=1;
usart_str_write("please choose:");
usart_str_write("1.) start");
usart_str_write("2.) stop");
do{
if ( i == '1')
{
usart_str_write("->execute");
USART_Write(0x0D);
read();
}
else
{
usart_str_write("please choose:");
usart_str_write("1.) start");
usart_str_write("2.) stop");
}
}
while(1);
}i run the codes( with interrupt)..
but why does the programme displays the menu selection continuously, instead of waiting for my input ( i.e. : usart_read)
i wanted the program to wait for my input, then go through the main program loop ( attention: the 'read()' must run continuosly !! )
and the program has to stop when i press '2'..
please help!!