Hello
I'm a mechanical engineer. I understand the basics of electrickery, but when it comes to electronic circuit design, you may as well sit me in the dunce's corner. I need some help.
I want to build a circuit that will drive an alternator warning light on a motorcycle. The bike has a typical Shindengen regulator/rectifier that controls voltage by dumping excess to ground basically like a Zener diode. There is no field current control.
I need a simple circuit that will identify when the output from the RR exceeds the battery voltage, and switch off the alternator light when it does.
What I had in mind was to look at the waveform of the system voltage. When the output from the RR is lower than the battery voltage, the system voltage is the same as the battery voltage and has a smooth DC wavefom. But when the RR output exceeds the battery voltage, an AC signal is superimposed onto the battery voltage because the RR supplies rectified AC with a "lumpy" waveform.
So, by installing a decoupling capacitor from the ignition circuit to ground, I should be able to separate the AC signal and do something with it. Specifically, use it to drive an SCR switching circuit that will operate the alternator light.
I've come up with a circuit below, but being the dunce I am with this sort of stuff, I have no idea whether I'm on the right track.
My twisted logic is that with a "flat" DC system voltage, a curret via R2 will hold the gate of the SCR open and allow it to conduct, thereby illuminating the lamp. With a "lumpy" system voltage, a small AC current will flow through the decoupling capacitor C2 and R3, causing Q1 to conduct, so shorting out the gate of the SCR and switching it off, thereby switching the light off.
Is this total bollocks, or does it have a chance of working?
If it is worth trying, are my component selections in the right ballpark? I'm guessing about a 2V minimum AC signal.
Cheers,
Cameron
I'm a mechanical engineer. I understand the basics of electrickery, but when it comes to electronic circuit design, you may as well sit me in the dunce's corner. I need some help.
I want to build a circuit that will drive an alternator warning light on a motorcycle. The bike has a typical Shindengen regulator/rectifier that controls voltage by dumping excess to ground basically like a Zener diode. There is no field current control.
I need a simple circuit that will identify when the output from the RR exceeds the battery voltage, and switch off the alternator light when it does.
What I had in mind was to look at the waveform of the system voltage. When the output from the RR is lower than the battery voltage, the system voltage is the same as the battery voltage and has a smooth DC wavefom. But when the RR output exceeds the battery voltage, an AC signal is superimposed onto the battery voltage because the RR supplies rectified AC with a "lumpy" waveform.
So, by installing a decoupling capacitor from the ignition circuit to ground, I should be able to separate the AC signal and do something with it. Specifically, use it to drive an SCR switching circuit that will operate the alternator light.
I've come up with a circuit below, but being the dunce I am with this sort of stuff, I have no idea whether I'm on the right track.
My twisted logic is that with a "flat" DC system voltage, a curret via R2 will hold the gate of the SCR open and allow it to conduct, thereby illuminating the lamp. With a "lumpy" system voltage, a small AC current will flow through the decoupling capacitor C2 and R3, causing Q1 to conduct, so shorting out the gate of the SCR and switching it off, thereby switching the light off.
Is this total bollocks, or does it have a chance of working?
If it is worth trying, are my component selections in the right ballpark? I'm guessing about a 2V minimum AC signal.
Cheers,
Cameron
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