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More ADC help needed

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AtomSoft

Well-Known Member
Hey guys. I recently started a topic on charging LEAD-ACID batteries and i think i know what to do but i need help in developing something to read the voltage of what seems to be a max of 12.65V ...

I would like to create a ADC using a Resistor divider to drop 13v to 5v. But calculating values isnt my strong point.
 

Pommie

Well-Known Member
Most Helpful Member
An 8k on the top and 5k on the bottom would work. Picking actual values yields 4.7k and 8.2k and that would give 5V out for 5+(4.7/5*8.2) = 12.7V.

Edit, increase the 8.2 if you want higher range.

Mike.
 
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AtomSoft

Well-Known Member
Pommie when you say 8k on top and k on bottom do you mean:

VCC(13v)<---8k---TAP---5k--->GND(0v)

heh it wont control the charge completely but via relay or something like that.

How would you go about it Gayan?
 
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Pommie

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Most Helpful Member
Pommie when you say 8k on top and k on bottom do you mean:

VCC(13v)<---8k---TAP---5k--->GND(0v)

Yes, because you will get the same current through both, you will get 8V across the 8k and 5V across the 5k.

Mike.
 

Yobortsa

Member
The ADC on the PIC will give you values from 0 through 1023, so if you can set up a Voltage Divider with the ratio 4.092 to 1 then 20.46V input will become exactly 5V (1023) on the output. This could be done with a POT so you can easily calibrate it.

Using this ratio, you can roll the ADC data to the right twice (mathematically this will halve, then halve again) to get the Voltage * 10. Much simpler calculation in a PIC than trying to multiply/divide.

Am I making any sense or just confusing? Did I get the maths correct?

David :)
 
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AtomSoft

Well-Known Member
1) Ok i found out i might need 15v as my max or 14v.... so regardless of top resistor i need a 5k resistor on bottom right? can i use a 10k pot set to 5k?

2) Also if i use 14v then 5k bottom and 9k top correct?

2) Also if i use 15v then 5k bottom and 10k top correct?
 

be80be

Well-Known Member
2) Also if i use 14v then 5k bottom and 9k top correct? you'll get 5 volts at the divider

2) Also if i use 15v then 5k bottom and 10k top correct? you'll get 5 volts at the divider
 

Noggin

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AtomSoft

Well-Known Member
2) Also if i use 14v then 5k bottom and 9k top correct? you'll get 5 volts at the divider

2) Also if i use 15v then 5k bottom and 10k top correct? you'll get 5 volts at the divider

great. I want to turn a max to a max. So if my max is 15v then i want it to be 5v max from pic. this way i just do some math to get the numbers.

so with this said each step should be around 15mV correct? or would it be around 45mv?
 
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