I bought a couple of Lithium Ion batteries on sale for $0.05 a piece. The are for a sony camcorder or something. I was wondering how I might charge them. I see there are chargers and chips to charge lithium polymer batteries. This battery seems to have 3 contacts on it. How do I tell which is which?
Hi,
It is relatively easy to charge Li-ion batteries, but only if done right.
If not done right they can explode and/or catch fire.
The main idea is to provide a limited charge current I until the voltage
reaches near 4.200 volts. It's common to stop before that though,
like 4.150 or 4.170 just so the charger doesnt go over 4.200 volts.
That 4.200v spec is pretty precise, so you have to use a circuit that
contains at least one voltage reference diode, either separate or
built into a regulator like the LM317 as audioguru pointed out.
There are some other precautions too though, such as the lower
voltage limit before damage occurs to the cell. It's said to be
2.500v, but it's good to keep the cell at 2.750v or above to be sure.
If the voltage *ever* drops below that level, it's a good idea to
not charge that cell anymore and just throw it out.
The max current level I is set when the voltage is around 2.75v
(low battery level) and that should be around 1/2 the ampere hour
capacity (in amps though) but 1/3 is common and lower too.
The simplest circuit is using an LM317 like this:
Set up the device to regulate the output at 4.15v or so (4.17v is ok too).
This requires the selection of two resistors, one of them is usually
220 ohms and the other sets the voltage output. If the other resistor
is a pot it should be a high quality pot because if the voltage jumps
up too high it could explode.
Once you have the voltage set (calculating that one resistor and adjusting
if needed once the circuit is built) you then set the current limit.
The simplest way is to use a power resistor on the input, say a 5 to
10 watt device. The resistor value is set to drop excess voltage from
the (presumably) wall wart. If you use a 9v wall wart and you have
about 4v output and the regulator drops 2v, then you need to drop
another 9-6=3v at whatever current. Say your output is 100ma.
3/0.100 is 30 ohms, or 33 would be ok too. The power rating must
be 3*3/33=273mw, so a half watt resistor should do it.
The entire circuit then is made from three resistors and an LM317 and
say a 9v wall wart.
You should check and double check the output voltage though, to
make sure it does not go over 4.200v or the cell gets ruined which
means the life is greatly reduced.