No, it will more than likely make a value lower than your smallest capacitor of 1000uF (1nF).
For series, use this equation:
1/ ((1/c1)+(1/c2)+(1/c3)+(1/c4).....+(1/cn))
where the ..... means (1/c) where c is the next capacitor. C1, C2, C3, C4, and CN are all capacitor values. Keep the units the same, and whatever unit you use, the result will also be in that unit.
For parallel, just convert the values to the same units and add the values.