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Nigel Goodwin said:Signal generator, scope (or AC millivoltmeter - NOT a multimeter), and a resistor - and apply ohms law!.
Be aware that the transmitter is series resonant, and the receiver parallel resonant.
Nigel Goodwin said:Place resistor between signal generator and transducter, use scope to monitor signal level across transducer. For transmitter adjust frequency for minimum signal. Measure signal BOTH sides of resistor, you can then work out the current through it, and from that the impedance of the transducer - simple ohms law.
Do the same with the receiver, but adjust for maximum, and use a much higher value resistor - to be honest, there's no real need to measure the receiver!.
epilot said:I am not able to produce a sine wave at the moment,my oscillator can generates a square wave, so how to CALCULATE the current of an square wave?(I am not sure if my multimeter has this ability)
epilot said:Nigel,
See if I am right?:
At first I connect a resistor in series with thransducer while they are connected to a 40khz square wave oscillator.
Then I must measure the voltage across the resistor and then i'll have the cureent of the circuit with ohm's law,
again I measure the voltage across the transducer and divide this voltage by the current to obtain the impedance ,yes?
2 questions:
What is the reason of adjusting the freq to the minimum for the transmitter and max for the receiver?
Why I must consider this:
transmitter is series resonant, and the receiver parallel resonant. ?