Does any one help to wire the counter IC 4017 to generate the negative pulse output since the input is clock signal.
I had found somewhere on the internet before but forgot, that the clock signal fed into the pin 15 or 13 ... and pin 14 to ground then outputs will produce negative decoded pulse???? correct me if I am wrong.
I need the negative pulses to drive the P-channel FET in the high power flashing circuit.
What does it mean "The 4017 will produce a high going 'positive' pulse on the decoded output" ?? my understand that the positive pulses are already done in the traditionnal diagram of 4017 IC. Or you have some advaced idea to advise.
the CD4017 counts at each high edge of the clock pulse incrementing the outputs to be high in sequence.
To drive a P-channel MosFet transistor the counter outputs must be inverted.
This can be done by inverting the counter output signals.
An easier way would be using N-channel MosFet transistors. N-channel MosFet transistors have the advantage of a much lower RDS(ON) than P-channel types.
the CD4017 counts at each high edge of the clock pulse incrementing the outputs to be high in sequence.
To drive a P-channel MosFet transistor the counter outputs must be inverted.
This can be done by inverting the counter output signals.
An easier way would be using N-channel MosFet transistors. N-channel MosFet transistors have the advantage of a much lower RDS(ON) than P-channel types.
Right! "from high to low"
good idea with CD4049, but more component to be crammed to the circuit.
Does any disadvantage if load's placed in the Source of N-channel mosFET?
Right! "from high to low"
good idea with CD4049, but more component to be crammed to the circuit.
Does any disadvantage if load's placed in the Source of N-channel mosFET?
The advantage of the load in the Drain, is that the Gate voltage can be less than the Load voltage.
eg:
say the FET Gate required a +5V to be turned ON, the Load could be connected to +12V.
If the Load was in the Source lead the +5V on the Gate would not fully turn on the FET, because of the voltage drop across the load, which would try to pull up the Source pin.
Do you follow that OK.?
If I understand, you want the High on the 4017 pin to turn OFF the current to the load.??
So all the Low pin loads would be ON, is that correct.?
Whats the load voltage supply also the 4017 supply.???
So your load must be on ground.
If the load is connected to the source of a N-FET then the source will be about 5 volts below the gate. Gate=12V and Source = 7V.
Infact my existing circuit is similar way to drive the power transistor and load feeding by 0V as motocycle electronic flashing unit (attached)
So that's why I need to replace the NPN power transistor Q2 by P-channel mosFET, but somebody advised the N mosFET is better. Power Supply is also 12VDC.
Infact my existing circuit is similar way to drive the power transistor and load feeding by 0V as motocycle electronic flashing unit (attached)
So that's why I need to replace the NPN power transistor Q2 by P-channel mosFET, but somebody advised the N mosFET is better. Power Supply is also 12VDC.
BTW my attached diagram is showing the motorbike turn flashing signal circuit to replace the traditional thermal flashing relay, so that why they hook the ground supply via loads (following the original concept of manufacturer), but as my experiment the circuit did not work well because when Q2 is on, the voltage at Emitter come up nearly with Vdd so cause the oscilation of Q1 is fail to supply and the flashing pace is disorder...
So I wonder if sombody help to solve this problem but keeping the traditional connection or have some good idea to improve it.