Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Having a trouble using the opto 4N35

Status
Not open for further replies.

sonaiko

New Member
I connected a 4.5v between terminals 1 and 2 [diode terminals].
i connected a 680ohm resistor between terminals 6 and the ground [emitter and the ground]
i connected a 5v to terminal 5 [collector].
I connected a 4.8Kohm resistor between terminal 4 and the ground [base and the ground]

GUYS NOTHING HAPPENS!!
when i turn on the Voltage source, or i turn it off i still get the same voltage readings on both of the resistors!!!

what did i do wrong? may anyone help?
 
sonaiko said:
I connected a 4.5v between terminals 1 and 2 [diode terminals].
i connected a 680ohm resistor between terminals 6 and the ground [emitter and the ground]
i connected a 5v to terminal 5 [collector].
I connected a 4.8Kohm resistor between terminal 4 and the ground [base and the ground]

GUYS NOTHING HAPPENS!!
when i turn on the Voltage source, or i turn it off i still get the same voltage readings on both of the resistors!!!

what did i do wrong? may anyone help?

If you connected 4.5V directly to the LED, with no current limiting, then you have probably blown the LED instantly!.
 
alright. i have used a new opto and added a limiting resistor. Still the same problem.
 
If you have everything connected correctly you should measure a little less than 5 volts across the 4.8k resistor from pin 4 to ground.

I am assuming that the 4.5 volts in series with the current limiting resistor is connected + to pin 1 and - to pin 2. That the + 5 volts is connected to pin5 and the - of the 5 volt supply is connected to the ground and/or the the other end of the resistors on pins 5 and 6.

The transistor should be in saturation, which means the voltage between emitter and collector is about 0.3 volts.
 
I connected a 4.8Kohm resistor between terminal 4 and the ground [base and the ground]
isnt the base being driven by the led ??
try disnonnecting the resistor to base..
 
i disconnected the resistor. Guys it worked, but after i raised the biasing voltage up to 13v!!! why it didnt work on 5v biasing?! weird!
 
sonaiko said:
I connected a 4.5v between terminals 1 and 2 [diode terminals].
i connected a 680ohm resistor between terminals 6 and the ground [emitter and the ground]
i connected a 5v to terminal 5 [collector].
I connected a 4.8Kohm resistor between terminal 4 and the ground [base and the ground]

GUYS NOTHING HAPPENS!!
when i turn on the Voltage source, or i turn it off i still get the same voltage readings on both of the resistors!!!

what did i do wrong? may anyone help?

Look at the diagram of the 4N35 and see which pin is the base and emitter.
 

Attachments

  • 4n35.gif
    4n35.gif
    3.7 KB · Views: 1,716
eblc1388 said:
Look at the diagram of the 4N35 and see which pin is the base and emitter.

ya, i dloaded the data sheet just before i begin my work.

It worked now, but after raising the biasing voltage to 13v. why is that?
 
biasing voltage?
are you saying you are using a voltage-divider to "bias" the output BJT and that voltage is at 13V!!!

I would suspect something is wrong with the opto, or it is not being drive/loaded correctly.


I am using some CNY75's on some of my gatedrivers and the only way to get the propogation delay down (4us the best I can get and that is no where good enough, but it is what it is).


Now I have a 56R burn resistor to the photo-diode - but that is being supplied from a 3V source (line reciever output).
On the secondary side I have ~1k pull-up and ~9k1 from the base to GND.
I say aproximately since each opto had to be calibrated, some needed 910R pullup (some downto 620R) equally the base needed 8k5 sometimes...

What exactly is the cct associated with the opto:
Including what is being used drive the opto. It might be what is being used has a low-current output and you are collapsing the voltage - I had that problem until I changed my line reciever to one that could source upto.

So if you could suppy that info I am sure we can figure it all out
 
I just realized why the original circuit would not work with the 680 ohm resistor from base to ground. When the emitter voltage got to about 0.7V the transistor went into cutoff because the with the emitter + the base is effectively negative.
If the 680 ohm resistor on the base is connected between the base and the emitter it would always work. As an alternate remove the 680 resistor, as for normal switching it would not be needed anyway.
 
The 4N35 has a minimum transfer ratio of 100%.
Sonaiko doesn't say what is the value of his current-limiting resistor for his LED, so maybe it is too high. With a 4.5V "biasing voltage" feeding the LED and its current limiting resistor, for the opto-transistor to conduct well into its 4.8k load resistor with a 5V supply, the value of the current-limiting resistor should be about 3.5K. If he used 12k or more, then a "biasing voltage" of about 13V will be needed to supply enough LED current. :lol:
 
Hi Sonaiko,
The transfer ratio for an optocoupler is how well the current in the LED causes the transistor to conduct collector current. With your 4.8k emitter resistor and a 5V supply, the max collector current is about 0.94mA. With its minimum transfer ratio of 100%, the LED current must also be at least 0.94mA. Its forward voltage is about 1.2V, so with 4.5V feeding the current-limiting resistor and LED then 3.3V will be across the resistor and its value will be 3.3/0.94m= 3.5k. :lol:
 
audioguru said:
Hi Sonaiko,
The transfer ratio for an optocoupler is how well the current in the LED causes the transistor to conduct collector current. With your 4.8k emitter resistor and a 5V supply, the max collector current is about 0.94mA. With its minimum transfer ratio of 100%, the LED current must also be at least 0.94mA. Its forward voltage is about 1.2V, so with 4.5V feeding the current-limiting resistor and LED then 3.3V will be across the resistor and its value will be 3.3/0.94m= 3.5k. :lol:

thanx dude! :wink:
 
Status
Not open for further replies.

Latest threads

Back
Top