finding LCM of {(1/x^0.5) + (1/x^1.5)}

[PG1995]

Hi

Could you please help me with this query? Thanks a lot.

Regards
PG

PS: There is a minor mistake in the attachment. Please check post #5's attachment.

 

[MrAl]

Hi,

Can't you just do the following (where i'll use the notation "sx" to indicate the square root of x)...

x^(3/2)=x*sx

So sx goes into x*sx, x times. So we place an 'x' over top of the first term giving us x/(x*sx) for the first term.
x*sx goes into x*sx one time, so we keep the '1' over top of the second term, giving us 1/(x*sx).
So we end up with:
x/(x*sx)+1/(x*sx)
which when simplified gives us:
(x+1)/(x*sx)

and i dont see any further simplification. So this was a matter of multiplying the denominators and then that as a common denominator and then simplifying.
Is that what you wanted to do?

 

[PG1995]

x^(3/2)=x*sx

Hi MrAl

I wish you could use the Latex!

Isn't it supposed to be x^(3/2)=x^3*sx instead of x^(3/2)=x*sx? Please let me know. Thank you.

Regards
PG

 

[steveB]

No, that's not correct. Consider the following law for powers.

x^a*x^b=x^(a+b)

Hence, x^(1/2) * x= x^0.5 + x^1 =x*(0.5+1)=x^(3/2)

 

[PG1995]

Thank you.

I get it now.

Regards
PG