Equation for pole 2 and 3 of a pot ?

First hi y'all, it's been a micro-while. (couple days)

I have to prepare a lab for tomorrow and we'll have an equation to formulate.

Let's say my Vsource is 20V and I have a pot of 100kΩ.

I need to find the equation that permits me to calculate the tension between pole B and pole C of the potentionmeter.

That part is about the dividers of tension.

Any hint ?

* it's all hooked in serial, eating puff cereals, and A on the pot is plugged on the + of the source, C goes back to source and B is my knob I guess.

ElectroNewby said:

* it's all hooked in serial,

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Are you sure the pot's not in parallel with the source?

ElectroNewby said:

eating puff cereals

Click to expand...

Is that one of those young-person jokes?

Everything you need is at Voltage divider - Wikipedia, the free encyclopedia

Yo. Finally I found out and was very simple: Vbc = Vs - Vab