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Electrolytic capacitor with less than 10% of rated voltage across it is OK?

Flyback

Well-Known Member
Hello,
C8, in the following schematic , is a 10uF electrolytic capacitor. It is rated 16V.
As you can see, it is across the Base-emitter of a BJT, thus it never gets any more than 0.7V across it.
Do you believe that this should be a ceramic capacitor instead?
 

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Electrolytic is fine for that purpose. You could go to a lower voltage unit if you like.
 
Thanks, but quoting page 11 of the book "IC555 projects" by E.A.Parr (babani publishers) "An electrolytic capacitor does not become a capacitor until about 0.1 of its voltage rating....."
book first published in 1978
book revised and reprinted n 1981
Book printed last in 2006.
 
The capacitor is just a bypass cap and does not appear to be a critical component so if it's capacitance is less than stated, it still should not be a problem. But if you are really concerned then use a 6V electrolytic or substitute a ceramic.
 
Its not a bypass cap, its a timing cap.
After the certain time , the capacitor will switch off the circuitry if the loads don't draw current.
Do you agree it wont look like 10uF, or even half of this?
 
C7 and C8 have this issue, if it is one.
I think placing a capacitor across B-E on a transistor does not make a good timer. The B-E voltage does not change much from on to off. I did not look at the data sheet but: If 0.65=off and 0.68=on that is not much change in voltage. The numbers might not be right. A 555 time uses 1/3 supply voltage change from on to off. Across R8 there is a 4 volt movement. That might be a better place for a timing capacitor.
 
I think the purpose of Q5/C8 is to turn Q4 on at startup. Once the system voltage gets to 9V (plus R9/C8 time delay) then Q5 turns on and lets the lockout system (Q4) work (no more current sourced through D5/6. Both capacitors will turn on slowly, and then, when one load opens, the Q4/C7 will delay the turnoff. I think the capacitors are there just in case there is a momentary dip in power so the whole system doesn't shutdown immediately, requires hard failure (loss of power for a certain amount of time). I don't think timing is critical. Q5 only turns off if system power drops below 9V, or at power off. So C8 (the 10uF) is really only used at startup, or 0V - 0.68V. If timing was critical, then they wouldn't use an electrolytic (-80 to +20% tolerance on a good day)

Putting a capacitor on a base/emitter junction is bad form, but I believe I remember reading somewhere in my foggy past that putting the capacitor on the base is like putting a much bigger cap on the collector... it uses the transistor's gain to amplify the capacitance (or looks like it's amplified). You could do the same thing, put a capacitor on the collector to hold the voltage constant (ish) when the transistor turns off/on, to slowly change that node's voltage, but you'd need a much larger one to do the same thing. I think they are just used to avoid spikes upsetting the system).
 
The book that I linked in #3 states that an electrolytic capacitor doesn't even become a capacitor until it has at least 10% of its rated voltage across it...Is this incorrect?
-It kind of makes sense because capacitors that are in storage tend, every few years, to get powered up to near rated voltage to keep them good.
 
Maybe the effect is similar to storage, where over time leakage will go up unless the cap is "reformed".
 

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