diode circuit
diode
The circuit can be solved by the LUCKY choice of case_2
NO further examination would be necessary since the circuit can have only 1 state.
HOWEVER, the states of the diodes was ASSUMED:
If cases_1, case_3, case_4 are assumed before case_2,
then these cases must be shown to be false assumptions
A circuit with multiple battery sources and 100 or 10,000 diode,resistor, would
require a computer program to solve the many equations involved.!
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refer to your ATTACHMENT
eq
a1 [1k 0][i1] = [ 5-Vd1+Vd2] // where i1,i2 are CW
b1 [0 1k][i2] [10-Vd2] // currents in loop A,B
a2 i1*1k + i2*0 = [ 5-Vd1+Vd2]
b2 i1*0 + i2*1k = [10-Vd2]
c1 Id1 = i1
d1 Id2 = -i1 +i2
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case_1
assume diode_1 conduct;
diode_2 cutoff so equation d1 above becomes
eq
1-d1 Id2 =0
1-a2 i1 =5v/1k =5ma
1-d2 gives Id2 =0 = -i1 +i2
1-d3 i2 =i1 =5ma !
1-d3 gives diode_2 conducts, BUT this contradicts assumption that diode_2 cutoff
therefore< diode_2 cutoff is a false assumption
and equation 1-d3 is not true
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case_2
assume diode_1,diode_2 both conduct:
: : : :
: : : :---> NO contradiction with assumption
therefore diode_1,_2 both conduct
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case_3
assume diode_2 conducts,diode_1 cutoff
: : : :
: : : :----> contradicts this assumption
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case_4
assume diode_1,diode_2 both are both cutoff
: : : :
: : : :----> contradicts this assumption
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hawk2eye