Defining a Bit with in an array

[The Real MicroMan]

I'm using a PIC with the CCS compiler I want to do the following

Set up an array such like:

int big[7];

Then I want to go to Byte 0 in the array and define a bit. Such like

#bit Little = Big[0].0

This statment does not work, I wand little to represent bit 0 in Byte Big[0]

Does any one know how to do this?

 

[bmcculla]

I don't know PICs but I know the 8051 which also has bit addressable memory.

8051 C compilers have compiler directives that let you specify the memory space. So for the Keil 8051 compiler:

bdata unsigned char Big[7];
bit Little = big[0].0;

should give you an array of 7 bytes in the bit addressable memory segment. That #bit looks like its specifying Bit addressable memory - You just need to find the compiler directive that specifies a byte of bit addressable memory.

 

[Oznog]

I think you'd use a union to define a bitfield. Haven't done it myself so I can't do an example right away.

 

[pittuck]

in c2c / boostc u would use

volatile bit name@address.bit

so

volatile bit little@big[0].7

Not tested, but apparently its ASCII C complient so it 'should' work..,