First of all find total impedance of the circuit:
Z=[(1/(9+j12))+(1/(9+j12))+(1/(9+j12))]^-1
Once you got Z, then you can find current supplied by the voltage source (240 V).
I=240/Z;
1. Complex Power: S=VI'
where I' means conjugate of I
2. What you will get when you do S=VI' is S=P+jQ.
P is your real or average power
3. Q is your reactive power
4. Magnitude of current:
I=240/Z as before and you will get I=Re{I}+j*Im{I}
where Re means real part
Im means imaginary part.
To get magnitude do following
[((Re{I})^2)+(Im{I})^2)]^0.5
5. Power factor: To get power factor draw a triangle with:
P=horizontal part and Q=vertical part
Now, P is always positive but Q can be either negative or postive.
tan (theta)=Q/P
power factor=cos(theta)
is theta>0, then lagging, if theta<0 then it is leading