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Circuit behavior

Homebrew

New Member
I built the circuit as shown and when i use a 6v 60mA bulb it lights to full brightness instantly, when i change the bulb to a 6v 160mA it glows faintly and takes almost 30 seconds to reach full brightness....can someone shine some light on this for me please (pun intended) lol
 

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You are probably drawing too much current from a 9V battery. At 60ma, it can supply enough current to light the bulb. At 160ma, you are maybe drawing too much current and the internal resistance of the battery is causing a voltage drop. As the battery overheats from excessive current, the internal resistance may drop.
Measure the voltage at the bulb when you try this, see what it shows. Also, measure the battery voltage with both bulbs, see if there is a difference.
You don't specify what kind of 9V battery you are using, I'm assuming the standard alkaline 9V type...
Also, having a transistor handling the current draw, and with a sagging voltage on the base, the transistor gain may limit the current as a start, then slowly increase if the battery voltage slowly increases.
 
I am running the circuit from my bench power supply set at 9v, i measure the voltage across the bulb and with the 60mA bulb the voltage is full instantly, with the 160mA bulb the voltage creeps up over several seconds.
 
The base current is only 8.7v/10000ohms = 0.8mA

The gain is not huge on this part ( from my search, it's an old germanium PnP) and your collector current is about 20mA or less.

Change the base resistor to 350 ohms to goose the base current to about 2.5mA.

Here's the datasheet I found.

 
Thankyou so much ZipZapOuch.....i dropped the value of the base resistor to 5K and it is almost instant response, now i just need to study the circuit more and play with some other values to understand the circuit, i am new to Electronics and i like to know how things work.....thanks aagain
 
Also, since you're using a 9v supply and your bulbs are rated for 6v, you should add a current limiting resistor in series with the bulb that dissipates 3v @ 160mA (use ohms law).

For the 160mA @ 6v bulb, you want to "drop" 3v at 0.160A, you need a 3A/0.160ohm = 18 ohm resistor (or 22 ohm).

For the 60mA bulb, use a 3v/0.060A = 50 ohms (or 47 ohm as a standard value, or two 100 ohm resistors in parallel)
 
I built the circuit as shown and when i use a 6v 60mA bulb it lights to full brightness instantly, when i change the bulb to a 6v 160mA it glows faintly and takes almost 30 seconds to reach full brightness....can someone shine some light on this for me please (pun intended) lol
I am impressed that you actually have a vintage Ge transistor. Zip Zap is correct that your base resistance is too high relative to the load resistance. That ratio ought to be the current gain times the load R = Rb, if we ignore Vbe drop for a bulb because the bulb resistance will rise as much as 12x the cold resistance at full brightness.

So why did it take so long? Your transistor junction was getting as hot as the bulb initially with only 4V across the bulb and Bipolar transistors love heat ( unlike FETs ) and this increases the mobility and current gain, in your case perhaps as high as 350 when hot. Unfortunately, like all things, aging takes a toll on hot parts and reduces their normal life expectancy 50% roughly every 10'C rise due to the Arrhenius Effect in Chemistry. So the current gain was increasing after the transistor got hotter, then the Vce voltage drop would reduce, and the lamp voltage would rise.
 
In addition to what others have said, the bulb will have a much lower resistance when cold. I would expect a bulb like that to initially take around 5 times the normal current if connected directly to a 6 V supply. The transistor is limiting the current and so it is taking longer to start up.
 

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