choosing the appropriate transformer

[bazramit]

Nothing energy from the second pulse will be stored, unless it's voltage is greater than the voltage already at the capacitor. So the only way to harvest energy from the second pulse is to either make it larger, or make the cap voltage from the first pulse lower than the second.

You might try using an inductor circuit like a buck converter.

-------D1----------L1-----------
            |               | 
           D2              C1
            |               |
           gnd             gnd

The cathode of two diodes is connected to the inductor, and should be schottky.

No guarantees, but this might give you some improvement.

Please give me some explanation about this circuit?

 

[ChrisP58]

Research the "buck converter" type of DC to DC converters.

But here are a few places to start with:
http://www.ecircuitcenter.com/Circuits/smps_buck/smps_buck.htm
http://www.smps.us/

 

[chemelec]

Research the "buck converter" type of DC to DC converters.

But here are a few places to start with:
http://www.ecircuitcenter.com/Circuits/smps_buck/smps_buck.htm
http://www.smps.us/

He want this to be SELF POWERED.
No ACTIVE CIRCUITS!

 

[()blivion]

He want this to be SELF POWERED.
No ACTIVE CIRCUITS!

I'm sure he is aware of this. The circuit provided is a PASSIVE buck design. It uses diodes as the buck switching elements. It has no external power supplies, batteries, computers, or any thing like that. Purely self powered. It just uses the Buck principal is all.

It's fairly strait forward.

 

[ChrisP58]

Thanks ()blivion.

And yes, there are no active components there. The idea is to use the energy storage capability of the inductor, in tandem with that of the capacitor, to maximize the energy capture of the input waveform.