I have this capacitor problem that I am thinking about for a few days now.
I have two capacitors charged separately:
Cap1: 6uF, 4V and Cap2 3uF, 1V.
Then they are connected in such a way as the positive terminal of one is connected to the positive terminal of the other.
Ao-----(-)| |(+) ----(+)| |(-)------oB
----- represents the wire. (-) (+) the polarity.
What type of connection is that?
It cannot be in series is that correct?
What is it going to happen?
The voltage difference between A and B is 3V.
So the capacitance of the combination will be
C = Q(total)/v = 27/3 = 9uF.
This is not the series capacitance.
The series capacitance is 2uF.
Are the capacitors in parrallel?
How could that be since their voltages are different.
This is a circuit class problem that I am trying to solve.
Any help please?
I have two capacitors charged separately:
Cap1: 6uF, 4V and Cap2 3uF, 1V.
Then they are connected in such a way as the positive terminal of one is connected to the positive terminal of the other.
Ao-----(-)| |(+) ----(+)| |(-)------oB
----- represents the wire. (-) (+) the polarity.
What type of connection is that?
It cannot be in series is that correct?
What is it going to happen?
The voltage difference between A and B is 3V.
So the capacitance of the combination will be
C = Q(total)/v = 27/3 = 9uF.
This is not the series capacitance.
The series capacitance is 2uF.
Are the capacitors in parrallel?
How could that be since their voltages are different.
This is a circuit class problem that I am trying to solve.
Any help please?