I have a capacitor of 30.000 uF, 35VDC
I am using a voltage of 30V, the capacitor is connected to a coil which has a resistance of 6 ohm.
This means my capacitor is fully charged at: 30V * 0,03F = 0,9 Coulomb.
With 6 ohm, my coil will use 30V / 6 hm: = 5 A.
And 0,9C / 5A = 0,180 seconds.
My question is: does this mean my capacitor will discharge in 0,18 seconds? Are there any other factors involved? capacitor resistance? -log() discharge speed? etc
Thanks
I am using a voltage of 30V, the capacitor is connected to a coil which has a resistance of 6 ohm.
This means my capacitor is fully charged at: 30V * 0,03F = 0,9 Coulomb.
With 6 ohm, my coil will use 30V / 6 hm: = 5 A.
And 0,9C / 5A = 0,180 seconds.
My question is: does this mean my capacitor will discharge in 0,18 seconds? Are there any other factors involved? capacitor resistance? -log() discharge speed? etc
Thanks