Continue to Site

Welcome to our site!

Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

  • Welcome to our site! Electro Tech is an online community (with over 170,000 members) who enjoy talking about and building electronic circuits, projects and gadgets. To participate you need to register. Registration is free. Click here to register now.

Calculating Resistors

Status
Not open for further replies.

ScuzZ

Member
I've read up everything I could about calculating resistors, but after entering the calculated resistor values into Livewire.. I get different voltages/currents.

What's going on..

I use the V=IR formula, but I get things like the attachment.

In the attachment, I was attempting to get an LED forward voltage of 1.5v at 30mA.

So R = V/I
R = 1.5/.03
R = 50 (Ohms)

But I get 2.3 volts.. :confused:
 

Attachments

  • Resistor.JPG
    Resistor.JPG
    19.1 KB · Views: 175
A LED is not a resistor.

If you look at the data sheet for LED you will see that it is expotential.

For example, if you gradually increase the voltage across a LED from zero, it will start to glow when the voltage across it reaches around 1.6 ~ 1.7 Volt.

So you need to look at the voltage versus current graph for the LED you are using and see what the voltage is at the current you wish to put through it. (or measure one with a multimeter)

You can then use Ohm's Law to calculate the series resistance.

eg. LED voltage 1.8 V @ 30 mA with a 5 V supply.

R = (5 - 1.8)/.03 = 106.7 Ohm, so use either a 100 Ohm or a 120 Ohm resistor.
 
Last edited:
So how do I get the LED to act under 1.5v @ 30mA?

It's only a simulation program, but I like to make sure my calculations are correct.

So R = V/I
R = (3 - 1.5) / .03
R = 50 Ohms

So by those calculations, the forward voltage over the LED would be 1.5v, correct?
 
Last edited:
Take ljcox's advice. You should start from the V-I characteristic of the LED you're using. In this case you should know the model or make a simulation and draw it. You can't decide both the voltage drop across the LED and the current arbitrarily.
 
If you want to apply the Ohm's law to the resistor, measure the current (Id) with the simulator. You'll find an operative point for the LED (Id, 2,3 V) and you will be able to use your equations after changing the supply voltage, for example.
 
ScuzZ said:
So how do I get the LED to act under 1.5v @ 30mA?
You can't. If the voltage across the LED was 1.5 V, the current through it would be VERY small. Look at the LED graph below.
ScuzZ said:
It's only a simulation program, but I like to make sure my calculations are correct.

So R = V/I
R = (3 - 1.5) / .03
R = 50 Ohms
So by those calculations, the forward voltage over the LED would be 1.5v, correct?
No.

I have attached a red LED graph that I drew for someone else. Ignore the red line for the moment.
 

Attachments

  • Graph 1.GIF
    Graph 1.GIF
    9.9 KB · Views: 178
ScuzZ said:
So how do I get the LED to act under 1.5v @ 30mA?
A red LED has a forward voltage of about 1.8V to 2.2V.
Tell your stupid sim program to try an IR LED that might have a forward voltage of only 1.5V.
 
hi scuz,
While you are studying resistance, lookup Conductance 'G'.

Regards
Eric
 
Status
Not open for further replies.

Latest threads

New Articles From Microcontroller Tips

Back
Top