# Battery life computation

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#### dpj

##### Member
hi...

I have stuck in battery life calculation.
Will someone validate this??

I have a 3.3V 1200mAh non rechargable battery;
my circuit consupmtion is such that for 1 second
it consumes 6mA and for 10 seconds it consumes
1mA; I need to compute for how long the battery
will last???

I have computed something like this; kindly confirm this for me please...

Average current consumed will be
{( 1 sec x 6 mA )+( 10 sec x 1 mA ) } / ( 1 + 10 )
that will be 16/11= 1.45mA

So battery life will be 1200 /1.45= 827 hrs
Is it correct???

#### MikeMl

##### Well-Known Member
Math looks ok. You can slightly improve the battery life by hanging a big capacitor across the battery terminals so as to reduce the ratio of peak to average current out of the battery.

#### Boncuk

##### New Member
Math looks ok. You can slightly improve the battery life by hanging a big capacitor across the battery terminals so as to reduce the ratio of peak to average current out of the battery.

... and decrease battery life time by the leakage current of the cap.

#### MikeMl

##### Well-Known Member
... and decrease battery life time by the leakage current of the cap.
Depends on the leakage current.

#### bountyhunter

##### Well-Known Member
I am not sure a capacitor would do anything because the load currents are so small that the battery's terminal voltage change will be negligible. I think the cap will just charge up and sleep for the rest of it's life. Maybe if there was an inductor ins eries with the cap, but it would have to be huge due to the long time constants the change occurs over.

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