yusuf Member Oct 4, 2012 #1 Hello guys , i have pc817 auto-coupler and i want take pin 1 & 2 of ic cd4093 high from the output of auto-coupler.. Please have a look..
Hello guys , i have pc817 auto-coupler and i want take pin 1 & 2 of ic cd4093 high from the output of auto-coupler.. Please have a look..
MikeMl Well-Known Member Most Helpful Member Oct 4, 2012 #2 Not "Auto-coupler", its an "PhotoCoupler", sometimes also called an Optical Coupler or Opto-Isolator. You are driving the input LED with a CMOS output, so you need a current limiting resistor between the CMOS output and the Anode of the LED. What supply voltage does the CMOS run on? What is the photo-transistor switching? Last edited: Oct 4, 2012
Not "Auto-coupler", its an "PhotoCoupler", sometimes also called an Optical Coupler or Opto-Isolator. You are driving the input LED with a CMOS output, so you need a current limiting resistor between the CMOS output and the Anode of the LED. What supply voltage does the CMOS run on? What is the photo-transistor switching?
yusuf Member Oct 4, 2012 #3 mikeml said: not "auto-coupler", its an "photocoupler", sometimes also called an optical coupler or opto-isolator. You are driving the input led with a cmos output, so you need a current limiting resistor between the cmos output and the anode of the led. What supply voltage does the cmos run on? What is the photo-transistor switching? Click to expand... Oh ! No ... Once again... i want cmos input from the photocoupler OUTPUT to cd4093. Photo-coupler input will run from direct 5v... And it will switch or take pin 1,2 of cd4093 high... FROM IT'S OUTPUT PIN.. Last edited: Oct 4, 2012
mikeml said: not "auto-coupler", its an "photocoupler", sometimes also called an optical coupler or opto-isolator. You are driving the input led with a cmos output, so you need a current limiting resistor between the cmos output and the anode of the led. What supply voltage does the cmos run on? What is the photo-transistor switching? Click to expand... Oh ! No ... Once again... i want cmos input from the photocoupler OUTPUT to cd4093. Photo-coupler input will run from direct 5v... And it will switch or take pin 1,2 of cd4093 high... FROM IT'S OUTPUT PIN..
MikeMl Well-Known Member Most Helpful Member Oct 4, 2012 #4 Very simple. Set up the input resistor R3 to get about 5mA through the Photo-Diode. Note that the circuit will not pass pulse rates above about 5KHz. Attachments Opt0-CMOS.jpg 126.7 KB · Views: 119 Last edited: Apr 9, 2013
Very simple. Set up the input resistor R3 to get about 5mA through the Photo-Diode. Note that the circuit will not pass pulse rates above about 5KHz.