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4-bit synchronous BCD up/down counter

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mehak

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sir i am making 4 bit BCD counter using D-flip flops for this i need just equations when x=1 and when x=0.. plz tell me is this rite or wrong???.... plz............
my sequnce is tha (D3), (D2) ,(D1), (D0) and flipflop inputs are shown as D4,D3,D2,D1. And outputs are D,C,B,A.
x=0,
D4=A'D+ABC
D3=B'C+A'C+ABC'
D2=A'B+AB'C'
D1=A'

x=1,
D4=B'C'D'
D3=B'C+C'B
D2=B
D1=A'

plz rpl me fast i have to submitt it tomorrow plz
 
plz help me plz... give me the state diagram and state table with characterstic table..... plz help me plz
 
Hi.

I cannot see what the logic you provided above have to do with the working of a counter :confused:

It looks to me like you've provided a solution that has nothing to do with the original problem.
 
present state next state:
SRQP x=0 x=1
0000 0001 1001
0001 0010 1000
0010 0011 0111
0011 0100 0110
0100 0101 0101
0101 0110 0100
0110 0111 0011
0111 1000 0010
1000 1001 0001
1001 0000 0000
 
flip flop inputs

x=0 x=1
D4 D3 D2 D1 D4 D3 D2 D1
0 0 0 1 1 0 0 1
0 0 1 0 1 0 0 0
0 0 1 1 0 1 1 1
0 1 0 0 0 1 1 0
0 1 0 1 0 1 0 1
0 1 1 0 0 1 0 0
0 1 1 1 0 0 1 1
1 0 0 0 0 0 1 0
1 0 0 1 0 0 0 1
0 0 0 0 0 0 0 0
 
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