230V 60W loghtbulb I=0,26?

Ok... a small (very stupid) question, I have a 230V 60W lightbulb so is I=0.26A then? So to speak a normal lightbulb draws about 260mA?

I have learned P=U*I
60=230*X|/230
0,26086..=I

I=0,26A?

Greets: The master n00b! (Hantto)

And i see that i have serious problems writing the subject correctly... "loghbulb" and "sloar"

Yes you re correct.

Power=Voltage*Current
or P = V * I


Therefore, 60 = 230 * I
or, I = 60/230
= 0.26 A
= 260 mA :idea:

:lol: