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How to prove that [ sin^(2)(x) + 2cos(x) - 1 ] / [ sin^(2)(x) + 3cos(x) -3 ] = 1 / [ 1 - sec(x) ]. I tried to use sin^(2)(x) = 1 - cos^(2)(x) and I can factor out a cos(x) in the numerator of LHS but not sure what I can do with the denominator.
Please see attached question for what I tried to...
Thanks for the responses. I don't know why this problem is in the back of the book if you are unable to solve it; but in either case it was a good exercise in problem solving!
The question is: Tuned Series RLC circuit is connected to 25mV source has Bandwidth of 10kHz and f1 (lower half power frequency) = 600kHz. Find R, L, C
First I calculated resonance frequency = 600kHz + (10kHz/2) = 605kHz and f2 = 610kHz.
After that I calculate Quality Factor Q = fr / BW =...
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