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Ok. I understand much better now.
**broken link removed**
So... this is the final, I guess. I can start building this, right?
Also, the 10KOhm resistor will be enough, I hope.
thank you for all the help you have given me.
**broken link removed**
This is what I got. I think I understand it much better now. Thank you very much for such a kind answer.
Although... one thing that irks me still is why the 5V is going through the LED, through the ULN2003, and to the IO pin. Isn't it supposed to be ground--since...
"remove the 10K, the CNTRL and the switch and replace the IC with an open collector inverter."
After that, it's this:
|||-----LED-----resistor1.2K------oc inverter-------\\\\\I-O\\pin\\\\\
But then, you started to talk about the tri-state buffer, which you told me to get rid of.
Please, be...
I hope I got this right
I hope I'll get this right the first time--is it?
**broken link removed**
When I want to read the value, I "open" the tristate buffer.
Oh wait, and you also said that the chip's not going to operate the LED... well, ignoring that for a moment, did I get it right?
I'm sorry for the crudeness of the drawing...
There are some HM 6116 Static-RAMs that I have, and I wanted to see if they worked.
I'm only going to use two address lines and one I/O bus line to simplify things.
Is there anything wrong that I'm doing? I'm especially worried about that...
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