Throbscottle and 4pyros,
I have connected 2 x 1uF polarised caps, as the circuit asks for a 1uF non-polarised, and I have read that this is a way of doing it???
Thats only to pass an audio signal!
You are making a power supply of sorts.
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Throbscottle and 4pyros,
I have connected 2 x 1uF polarised caps, as the circuit asks for a 1uF non-polarised, and I have read that this is a way of doing it???
Thats only to pass an audio signal!
You are making a power supply of sorts.
Yes that is an acceptable way to make a non-polarised cap from twp polarised caps. However the circuit does not need a non-polarised cap! Just use a normal 1uF cap with it's - lead to ground.
You are only half wave rectifying the transformer signal, so you are getting all the power transferred as DC. This will be causing issues over time with the sound card output as it is capacitor coupled.
Replace the diode with a 4 diode "bridge rectifier" so that balanced AC is used from the soundcard->transformer->transistor base. Also you need a resistor across the transistor base (base to gnd), try about 470 ohms to 2.2k. That will give a more defined ON/OFF point and give better relay turnoff.
Everything up to the transistor looks good. I would suggest you try that with the relay and check the "fading" problem is all fixed now, if that test ok then you could change to the opto coupler, which could ideally replace both the transistor and relay.
If it is the soundcard speaker or headphone outlet (not the line outlet) it has enough power to drive a 16 ohm headphone at maybe 100mW or more, so that would be enough to make a few mA through the LED in the optocoupler.
If you are eliminating the transformer and putting the bridge rect directly on the sound card speaker output use a 15 ohm resistor in series, and a resistor across the LED like 2k7. That is assuming you can tweak the soundcard output level via the PC so you don't kill the LED from being too loud. It might be wise to start with say a 1k resistor in series instead of the minimum 15 ohms, for LED safety, and then tweak the value of that resistor until you get good performance.
If you had a 'scope it gets easier as you could drive the soundcard output into a resistor and measure the voltage/current etc that it will provide.
If it is the soundcard speaker or headphone outlet (not the line outlet) it has enough power to drive a 16 ohm headphone at maybe 100mW or more, so that would be enough to make a few mA through the LED in the optocoupler.
If you are eliminating the transformer and putting the bridge rect directly on the sound card speaker output use a 15 ohm resistor in series, and a resistor across the LED like 2k7. That is assuming you can tweak the soundcard output level via the PC so you don't kill the LED from being too loud. It might be wise to start with say a 1k resistor in series instead of the minimum 15 ohms, for LED safety, and then tweak the value of that resistor until you get good performance.
If you had a 'scope it gets easier as you could drive the soundcard output into a resistor and measure the voltage/current etc that it will provide.
Are you measuring the 40mV using your multimeter on AC range? That is not an accurate reading, probably due to the meter being optimised to 50/60Hz measurement and the soundcard signal being hundreds of Hz.
If you don't have a scope it's abit harder to measure but you can still do a simple test. You are on the right track seeing if a LED light s up. Just try the bridge rectifier and LED with a small cap across the LED like 0.1uF. Use a smaller series resistor than 1k, try 100 ohms or 220 ohms. Then slowly turn up the sound card and the LED should light when the soundcard output voltage is greater than the rectifier drops (about 1v) plus the LED drop (about 1.3v).
If your soundcard only makes 1.2v after the rectifier you have probably connected to the line out plug, which only makes about 2v p/k when turned right up and is designed to drive powered speakers and amplifier inputs. You need to connect to the headphone plug (the LOUD output) which drives a headphone or small speaker directly.
It may need to be properly loaded to see the right voltage. Cheak it with the headphones attached if you can.40mV is not right for a headphone output! The line output should be 1-2v p/p and the headphone output up to a few volts, and a 16 ohm headphone set should pretty much blow your ears off if it is turned up fully. Do you have some headphones/earphones around?
40mV is not right for a headphone output! The line output should be 1-2v p/p and the headphone output up to a few volts, and a 16 ohm headphone set should pretty much blow your ears off if it is turned up fully. Do you have some headphones/earphones around?
If you are getting 40mV p/p on the scope from the headphone output, how many volts p/p do you get from the line output plug?
Also what is generating the audio signal to the soundcard and does that have a volume control? Maybe it is turned right down?
i'd like to ask a question here about the radio..... what is it? is it a radio that has SSB capability? if so you can eliminate the whole hassle of building a keyer, and feed the radio audio from the sound card. a single frequency tone (like what i assume you are feeding the keyer with) will act like a CW carrier on an SSB radio. this is how most CW is done these days. the transmit switch is held down and the audio tone creates the carrier. so if the radio is tuned to 14.000 MHZ USB and your tone is 1khz, the CW is transmitted on 14.001Mhz.
That should be able to light an LED. Have you tryed it with a low value current limting resister?When connected into the circuit, loaded by transformer. Primary 1V, secondary 3V, after rectifier, 1.2V.
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Regarding the circuit, it seems that the rectifier part takes all of the energy out of the system.