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Thanks a lot, misterT.
I believe you have it right because otherwise there is no easy way to solve it as far as I can tell. Yes, the attached table in your post gives the correct value for 'p'. I have also checked the table given in the book but unfortunately I don't even know how to read the values of 'p'. For instance, how do I find p=0.4 from table? As you can see values for 'p' are given as: 0.01, 0.02, 0.03, 0.04, etc. Please help me. Thank you.
Could you please also help me with this query? Thanks.
no way out! Is there? Kindly help me. Thanks.
I plugged that equation in WolframAlpha and it gives the right answer: https://www.wolframalpha.com/input/...*(p^2)*(1-p)^13+++455*(p^3)*(1-p)^12+=+0.0905
(Of course there are 15 possible solutions, but one of them is p=0.40).
It would be a burden to solve that by hand. So, I really think that the problem is supposed to be solved using tables or computer.
Good thing is that all the work you did is correct. The equation you ended up with gives the right solution. I would not like to solve it by hand.. I know there are plenty of tricks you can do, but I have forgotten most of them. If I would try to solve that by hand first I would take logarithm from both sides. That would change the exponentials to multiplications..
I meant "plot the function" in that plotting the function helps to find the real solutions. Nice to see it there too though
It is not easy to plot 15th order function.
Yes, but the solution requires the use of cumulative probability.. I don't understand your point there. Are you saying that I made a mistake or PG made a mistake?
The table I provided (cumulative table) is the one that should be used.. PG posted the wrong table.