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230V 60W loghtbulb I=0,26?

Discussion in 'General Electronics Chat' started by hantto, Nov 6, 2002.

  1. hantto

    hantto Member

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    Ok... a small (very stupid) question, I have a 230V 60W lightbulb so is I=0.26A then? So to speak a normal lightbulb draws about 260mA?

    I have learned P=U*I
    60=230*X|/230
    0,26086..=I

    I=0,26A?

    Greets: The master n00b! (Hantto)
     
  2. hantto

    hantto Member

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    And i see that i have serious problems writing the subject correctly... "loghbulb" and "sloar"
     
  3. kinjalgp

    kinjalgp Active Member

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    Yes you re correct.

    Power=Voltage*Current
    or P = V * I


    Therefore, 60 = 230 * I
    or, I = 60/230
    = 0.26 A
    = 260 mA :idea:

    :lol:
     

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