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| I have the checked out the following link http://www.kmitl.ac.th/~kswichit/LFrobot/LFrobot.htm These are the problems i am facing. 1. This is a robot for following black line. I need my robot to follow a white line. 2. we are very new to microcontrollers, and rom writing Hence when he says, "MY Code" and then there is a follow up in it. Could someone explain how this program works and how one can modify it to follow a white line on a black background. 3. In the link given as robot_asm what does the initial paragraph mean. Help needed urgently. | |
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| The 4 sensors output a digital '1' when it sees white and a '0' when it sees black. You can modify the code to invert the input which will switch the black and white. You could also switch the inputs to the opamps to invert the sensor outputs. For rom writing you need to look at the website of the manufacturer of your microcontroler. | |
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| thanks for the reply. could you just tell me where exactly, i mean which part of the code, you see this digital '1' or digital '0' coming out. It would be very helpful if you can just explain me the program under "My Code" "You could also switch the inputs to the opamps to invert the sensor outputs. " hope you have seen the circuit, but switching inputs just puts the sensor cutdown right. | |
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| this was written for an 8051 .. it could probably be adapted to your processor.. what controller are you using? Code: *#cpu 8051 Tiny
*
* DDS MICRO-C 8031/51 Startup Code & Runtime library for TINY model
*
* Copyright 1991-1999 Dave Dunfield
* All rights reserved.
*
ORG $0000 $0800 CODE Starts here (Normally in ROM)
LJMP START
ORG $0003
LJMP SERVICE_EX0
ORG $000B
LJMP SERVICE_TIMER0_INTERRUPT
* Fixed memory locations for alternate access to the R0-R7 register bank.
* If you are NOT useing BANK 0, these equates must be adjusted.
?R0 EQU 0 Used for "POP" from stack
?R1 EQU ?R0+1 Used to load index indirectly
?R2 EQU ?R0+2 "" "" "" ""
?R3 EQU ?R0+3 Used by some runtime lib functions
?R4 EQU ?R0+4
?R5 EQU ?R0+5
?R6 EQU ?R0+6
?R7 EQU ?R0+7
*
* Startup code entry point
*
* If you are NOT using interrupts, you can reclaim 50 bytes
* of code space by removing the following TWO lines.
* AJMP *+$0032 Skip interrupt vectors
* DS $0032-2 Reserve space for interrupt vectors
*
START EQU *
MOV SP,#?stk-1 Set up initial stack
ORL TMOD,#%00000001 set timer 0 to be counter 16 bit
SETB IE.7 $AF EA
SETB IE.1 $A9 ET0 Enable timer 0 interrupt
SETB TCON.4 start timer 0
LCALL main Execute program
SJMP * JUMP HERE
* EXIT to MON51 by calling the 'timer1' interrupt vector ($001B).
* This causes MON51 to think that a single-step operation has just
* completed, and therefore it saves the user registers, and performs
* a context switch back to the monitor.
*
* When using 2K addressing (CC51: -Z option, ASM51: -A option) this LCALL
* may fail "Out of range" because it gets translated to ACALL, and $001B
* may not be in the same 2K block as your program. Since 2K devices cannot
* support a debugger, change the ORG to $0000, and ...<continue below>...
*
* If you are NOT using MON51 (or MONICA which works the same), you will
* need to change this to whatever action you desire when main() returns.
* Suggestions: 1:freeze (SJMP *) 2:Restart (SJMP *&$FF00)
exit LCALL $001B Call Timer-1 interrupt
SJMP exit Incase he go's again
**************************** My code *********************************
SERVICE_TIMER0_INTERRUPT EQU *
PUSH ACC
PUSH PSW
MOV TH0,#$FF reload timer 0 for ms
MOV TL0,#$00
INC tick
MOV A,tick
CJNE A,#100,RIGHT
MOV tick,#0
RIGHT
CLR C
SUBB A,speedright
JC ON_RIGHT
CLR P1.0
SJMP LEFT
ON_RIGHT
SETB P1.0
LEFT
MOV A,tick
CLR C
SUBB A,speedleft
JC ON_LEFT
CLR P1.1
SJMP EXIT_I
ON_LEFT
SETB P1.1
EXIT_I
POP PSW
POP ACC
RETI
SERVICE_EX0 EQU *
INC cputick
RETI
$SE:1
*#map1 Segment 1, initialized variables
$SE:2
*#map2 Segment 2, internal "register" variables
ORG $0008 Internal ram ALWAYS starts here
tick DS 1
speedright DS 1
speedleft DS 1
cputick DS 1 | |
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| yes i am using 8051 micorprocessor only and hte controller is the same mentioned in hte website. could you make us understand in plain terms what the program is doing. Like for example PUSH ACC PUSH PSW MOV TH0,#$FF reload timer 0 for ms MOV TL0,#$00 INC tick MOV A,tick CJNE A,#100,RIGHT MOV tick,#0 What is happening once the programme starts from the first statement. With that we will know where exactly one can modify the code and get the desired output. As you say it is only the alteration of logic '0' and logic '1' that is to be done. Secondly, when you say "You could also switch the inputs to the opamps to invert the sensor outputs. " do you mean to say that this is another alternative, the first being altering the code. The latter one requires the hex code to be altered, could you tell me where i should be doing that. Thanks for the reply.
__________________ Will always be interested in knowing the web of technologies around. | |
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| an altered progrom for the 'my code' thereby making it follow the white line would be most welcome | |
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| i have a question.. what assembler are you using ? | |
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| Quote:
You would swap the + and - (inputs) on the op amps. so for sensor one, instead of the + (pin 3) being connected to the 20k pot, it would be connected to the photo transistor (where pin 2 of the op amp is connected) and pin 2 would go to the 20k pot. you should be able to use the code as-is then...
__________________ Jeff Zimmerman To the optimist, the glass is half full. To the pessimist, the glass is half empty. To the engineer, the glass is twice as big as it needs to be. | ||
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| You can change the code without too much trouble replace : sensors = (P3 &=0x0f); with : sensors = ((~P3) & 0x0f); All this does is take the bits in from the sensor and change all the ones to zeros and and zeros to ones. The ~ is the bitwise NOT operation. | |
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