what if he enters something else, string for example?
Hello All:
Would appreciate some help on converting the contents of an array to an integer. User enters data and it is stored into an array, but how can i convert the contents to an integer.
Here is what I have for adding the data to the array, until either 3 characters are entered from 0-9 or until the escape or enter key.
Say the user enters 1 and then enter, the array would be 100, or the user could enter 001 and then enter, the value is 1 but how to pull it out of the array so it is a number of 1. I suppose I could pad the array with FF and test each value in the array, and multiply the placeholders by 1,10,100 and add them together?. Any suggestions ?.
Code :unsigned char i; unsigned int array[3]; unsigned char x; do { while(!DataRdyUSART()); //polls receive buffer for available data i = ReadUSART(); // read a single character from buffer if ( ('0' <= i) && (i <= '9') && (x >=0) ) { array[x]=i-Ascii; // Add to array printf("%c",i,0); //display on terminal; x--; } } while ( 13 != i && 27 != i);
Last edited by bryan; 19th April 2012 at 01:47 AM.
what if he enters something else, string for example?
Can't as the code only allows 0-9 to be to be entered, unless I am missing something?
can integer be negative?
if not you could do something like
Code :unsigned char i; //unsigned int array[3]; unsigned char x; int temp; do { temp=0; // init temp as zero while(!DataRdyUSART()); //polls receive buffer for available data i = ReadUSART(); // read a single character from buffer if ( ('0' <= i) && (i <= '9') && (x >=0) ) { temp=temp*10; // adding digit, multiply temp by 10 and then... temp=temp+ i - '0'; // add current digit } } while ( 13 != i && 27 != i);
Thank you very much panic mode. That did the trick. So simple and efficient, can get rid of the array.
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