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| The emitter current in the 2n2222 will be limited by the Beta of the 2n2222. This will vary with different 2n2222s. So it would be best to eliminate the 120R resistor in the base and put a resistor in the 2n2222s emitter lead instead. Choose the emitter resistor so that the TIP41 will saturate properly for the given load. Or get rid of the TIP41 and 2n2222 and replace them with a TIP121 instead.
__________________ --- The days of the digital watch are numbered. --- Last edited by kchriste; 12th October 2007 at 04:15 AM. | |
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| Hi thanks for the expert comments. It was very useful. I must work out according to the specifications given from you. Thanks for that. | |
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| Hi, That link worked for me too. Back to the question, if the connection is as kchriste suggested, then where should the 1 k So basically the resistor that used to prevent the leakage current from turning on another transistor is needed when there are paired transistors? Thanks
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| You have it correct, BananaSiong. The 1K resistor helps to offset any leakage caused by the 2n2222 and also any Collector-Base leakage in the TIP41 itself. While these leakage currents are negligible under normal operating conditions, they can become a problem at very high temperatures hence the inclusion of the resistor in a good design.
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| Thanks kchriste. In the darlington pair, I see there are two resistor built in. Each of the transistor has one resistor across the base and emitter as attached. So the 200
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| Yes, the same reason. | |
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