Before, I used the A/D capability of PIC16f877 to function as a 5V voltmeter and display it in a 16X2 LCD Display.

this time, I want to measure current,

how do i measure current in PIC? i just want to create a prototype and what ICs do I have to use? thanks.

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Learning is a life-long process...

 

It's the same as measuring the current with anything else, you measure the voltage drop across a resistor. In order to keep the voltage drop across the resistor low you need to amplify the voltage, an opamp in differential mode is usually used to do this.

The biggest problems are providing power for the PIC and opamp, if you have a seperate supply for them it's no problem, otherwise you need to get a little inventive!.

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PIC programmer software, and PIC Tutorials at:
http://www.winpicprog.co.uk

 

Take a look at Allegro Micro: http://www.allegromicro.com/

Kent

 

Just use a shunt like this http://www.mouser.com/index.cfm?hand..._pcodeid=66211

That particular one will drop .01 V/amp drawn across it.

If you are talking about smaller currents, use a larger value shunt.

You can use an op-amp to multiply the voltage and measure that, or you can get a precision voltage referance and hook that to the PIC as the upper voltage referance. That way you can have 10-bit resolution between gnd and the reference voltage (switch between different referances and you get different ranges)