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Thread: Looking for a sheet that resists

  1. #256
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by dknguyen View Post
    If you seriously believe crashsite is trying to make shoes that would allow him to walk on the surface of the sun...then that would explain a lot.
    I could define trying in this context in at least two different ways. First, considering the factors involved. Second, doing so within a lifetime. And maybe there is a third possibility - comparing scenarios.
    Last edited by jasonbe; 12th July 2009 at 12:39 AM.
    She 'tis not there.


  2. #257
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    Quote Originally Posted by jasonbe View Post
    Its still taking me a while to figure this one out. At Sheet resistance - Wikipedia, the free encyclopedia, if I understand the forumula, I can substitute Wt for A. However, doing so is not intuitively clear to me. How can the resistance offered by a material have nothing to do with where the electrical contacts are made on it? I might be totally misunderstanding the formula. I am not clear specifically what L means in the formulas R=pl/A=pL/(Wt).
    Sheet resistance is no different to the resistivity of a cable, just replace the cross-sectional area with W×t, where W is the width and t is the thickness.

    Please attempt the following problems:

    I have a sheet 2mm thick, 50mm wide and 2m long and is made of a material with a resistivity of 2.5mΩ·m, what's the resistance of the sheet?

    I need a sheet 5mm thick, 100mm wide and 0.5m long with a resistance of 1k, what resistivity material do I need?

    Note you'll need to convert all the prefixes to base units: i.e. replace mΩ with 0.001Ω, and mm with 0.001m before doing any calculations otherwise you'll go wrong.


    R = \rho \frac{L}{A} = \rho \frac{L}{W t}
    Last edited by Hero999; 12th July 2009 at 10:21 AM.

    I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong.

    Please ask on the open forum if you have a question and I'll be happy to help,
    if I know the answer.

  3. #258
    dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent dknguyen Excellent
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    Quote Originally Posted by jasonbe View Post
    I could define trying in this context in at least two different ways. First, considering the factors involved. Second, doing so within a lifetime. And maybe there is a third possibility - comparing scenarios.
    Blah blah blah. Troll.
    Tanaka Sensei (avatar) says: Please spell it "ridiculous" correctly! Not "rediculous". ^^

  4. #259
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    Quote Originally Posted by Hero999 View Post
    Note you'll need to convert all the prefixes to base units: i.e. replace mΩ with 0.001Ω, and mm with 0.001m before doing any calculations otherwise you'll go wrong.
    Actually, that wont help too much. What he needs to convert is his mind away from his childish, pointless game. There's probably not much point in suggesting that he try to convert it to anything involving electronics or technology since it's obvious that the only interest he has in any of that is in how to use it to continue his ploy.

    I admit it. I was wrong. I thought he'd pretty well exhausted the range of piddly, pointless ploys to keep his game alive. But, this one was his next move. We should learn from it.

    Of course, he's not going to let on that he's trying to actually understand anything but, he's now going out and doing searches on the internet to come up with some semi_related, esoteric crap that he can pretend that he needs assistance with. Ohm's Law is too "useful" so, he throws out some formulas he found on Wiki as his way to cry out for his next his next round of attention.

    Okay, you gave hime a simple problem and some prompts. Let's see if he manages to actually come up with the correct answer (BTW: that grinding noise you are hearing is the rusty wheels turning in his head as he figures out how to make sure that the correct answer is the last thing he will come up with).

    He has vectored around my predictions in the past but, I don't think he can vector around this one (at least not by doing what he knows is the right thing) without tipping his hand.

    As I said, watch and learn, boys and girls.

  5. #260
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by Hero999 View Post
    Sheet resistance is no different to the resistivity of a cable, just replace the cross-sectional area with W×t, where W is the width and t is the thickness.

    Please attempt the following problems:

    I have a sheet 2mm thick, 50mm wide and 2m long and is made of a material with a resistivity of 2.5mΩ·m, what's the resistance of the sheet?

    I need a sheet 5mm thick, 100mm wide and 0.5m long with a resistance of 1k, what resistivity material do I need?

    Note you'll need to convert all the prefixes to base units: i.e. replace mΩ with 0.001Ω, and mm with 0.001m before doing any calculations otherwise you'll go wrong.


    R = \rho \frac{L}{A} = \rho \frac{L}{W t}
    Is this formula used to estimate the resistance between point electric contacts on a sheet? I don't know what L means.
    She 'tis not there.

  6. #261
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by dknguyen View Post
    Blah blah blah. Troll.
    Putting aside my opinion about the appropriateness of your response, if it was in response to anything that I wrote that implied that you shared crashsite's sentiments, then I have not made that determination.
    She 'tis not there.

  7. #262
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by crashsite View Post
    Actually, that wont help too much. What he needs to convert is his mind away from his childish, pointless game. There's probably not much point in suggesting that he try to convert it to anything involving electronics or technology since it's obvious that the only interest he has in any of that is in how to use it to continue his ploy.

    I admit it. I was wrong. I thought he'd pretty well exhausted the range of piddly, pointless ploys to keep his game alive. But, this one was his next move. We should learn from it.

    Of course, he's not going to let on that he's trying to actually understand anything but, he's now going out and doing searches on the internet to come up with some semi_related, esoteric crap that he can pretend that he needs assistance with. Ohm's Law is too "useful" so, he throws out some formulas he found on Wiki as his way to cry out for his next his next round of attention.

    Okay, you gave hime a simple problem and some prompts. Let's see if he manages to actually come up with the correct answer (BTW: that grinding noise you are hearing is the rusty wheels turning in his head as he figures out how to make sure that the correct answer is the last thing he will come up with).

    He has vectored around my predictions in the past but, I don't think he can vector around this one (at least not by doing what he knows is the right thing) without tipping his hand.

    As I said, watch and learn, boys and girls.
    The formulas that I am - to use your word, throwing out, are ones that relate resistance to distance. I am not sure what these forumlas define because I don't know how L is described. I have not given up on Ohm's law. I am only looking for a way to describe resistance as a function of distance - whether this involves combining Ohm's law with another equation or not. Notwithstanding your statement, I think that this involves electronics.
    Last edited by jasonbe; 12th July 2009 at 10:28 PM.
    She 'tis not there.

  8. #263
    jasonbe Bad jasonbe Bad
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    It would be helpful if someone would tell me if L in R = pL/A = pL/(Wt) - at Sheet resistance - Wikipedia, the free encyclopedia, means length of the sheet, the length between arbitrarily located point electrical contacts on the sheet, and/or the length between a different type of electrical connection resulting in a uniform current through a line defining a side of the sheet - and perhaps a uniform current through the opposite side as well.
    Last edited by jasonbe; 12th July 2009 at 10:48 PM.
    She 'tis not there.

  9. #264
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    Quote Originally Posted by jasonbe View Post
    Is this formula used to estimate the resistance between point electric contacts on a sheet?
    It's the formula to estimate the resistance form one end of a sheet to the other.

    I don't know what L means.
    Read the Wikipedia artical, it should be fairly obvious.

    It would be helpful if someone would tell me if L in R = pL/A = pL/(Wt) - at Sheet resistance - Wikipedia, the free encyclopedia, means length of the sheet, the length between arbitrarily located point electrical contacts on the sheet, and/or the length between a different type of electrical connection resulting in a uniform current through a line defining a side of the sheet - and perhaps a uniform current through the opposite side as well.
    I will not try to help you any more unless you answer the problems I set you in my previous post.

    I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong.

    Please ask on the open forum if you have a question and I'll be happy to help,
    if I know the answer.

  10. #265
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by Hero999 View Post
    It's the formula to estimate the resistance form one end of a sheet to the other.


    Read the Wikipedia artical, it should be fairly obvious.


    I will not try to help you any more unless you answer the problems I set you in my previous post.
    It is obvious to me that L has something to do with the length of the sheet. It is not obvious to me if the formula is independent of the location of electrical contacts; if L means the distance between electrical contacts; if L does mean the distance between electrical contacts - if the electrical contacts as implied by the formula have to be point contacts, or if the electrical contacts have to be such that there is one or two uniform currents through lines defining opposite sides of the sheet.
    She 'tis not there.

  11. #266
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    I'm trying to figure out if a formula - Rs = (V/I) * CF - at Sheet Resistance might apply. Does anyone know another name for CF that I can use in a search?
    She 'tis not there.

  12. #267
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    Quote Originally Posted by jasonbe View Post
    I'm trying to figure out if a formula - Rs = (V/I) * CF - at Sheet Resistance might apply. Does anyone know another name for CF that I can use in a search?
    You have to learn to walk before you can learn to run. I would suggest that we withhold all technical assistance from this guy until he shows that he has at least taken the effort to learn and be able to apply, Ohm's Law.

    I love the idea of putting the ball in his court and watching him squirm as he conives ways to try to continue groveling for attention without actually showing any cognizance.

    It surely shouldn't be too difficult for a guy who is asking for detailed technical information on advanced levels to be able to show compentency in something taught in the first week on any high school level electronics class.

    Okay, okay...I thought I could do it and, bleieve me I wrestled with my demons (and lost) so...

    Perhaps an appropriate search for CF for you might be, "c**t face"?

  13. #268
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    I love the idea of putting the ball in his court and watching him squirm as he conives ways to try to continue groveling for attention without actually showing any cognizance.
    I think hes doing rather well being you keep giving him the attention! Direct attention or not, he is still hanging in there thanks to you!

    Crashsite 0
    Jasonbe 1


    I am almost half tempted to give jasonbe positive rep points just for playing you guys so very well!

    As inept as he may look at electronics and electrical theory he obviously knows how to play this game and he is playing it very very well!
    "When in doubt, LIGHT IT ON FIRE AND SEE WHAT COLOR OF SMOKE IT CAN MAKE!" -- tcmtech

  14. #269
    jasonbe Bad jasonbe Bad
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    Quote Originally Posted by crashsite View Post
    You have to learn to walk before you can learn to run. I would suggest that we withhold all technical assistance from this guy until he shows that he has at least taken the effort to learn and be able to apply, Ohm's Law.

    I love the idea of putting the ball in his court and watching him squirm as he conives ways to try to continue groveling for attention without actually showing any cognizance.

    It surely shouldn't be too difficult for a guy who is asking for detailed technical information on advanced levels to be able to show compentency in something taught in the first week on any high school level electronics class.

    Okay, okay...I thought I could do it and, bleieve me I wrestled with my demons (and lost) so...

    Perhaps an appropriate search for CF for you might be, "c**t face"?
    Crashsite in the post that I am responding to compares learning Ohm's law,
    V = IR, with learning how to walk. I don't want to write anything that would discourage people from participating in this site because of math. However - while the math for this formula might not seem to be the most advanced, the molecular activity associated with it seems to me as though it could be studied in depth. How much crashsite believes that a person should know about molecular activity associated with this formula before participating in this site, I do not know. Perhaps there are simplified ways of describing the basics of molecular activity that relate to Ohm's law and maybe even describe it partially or in full. I can't say that I understand the basics at this time - and I don't know if they are known by anyone at this time.

    The formula can be rewritten as R = V/I. The term that I meant to express interest in is a constant multplied by V/I. Putting the chemical significance of the term aside - which might be considered acceptable to do if crashsite is accurate in saying that Ohm's law might be taught in the first week of a high school course, mathematically, V/I does not seem too much more difficult to calculate than a constant multiplied by V/I. In this case, the constant is CF - which I think is the resistance correction factor, and the overall equation is (V/I)*CF.

    I would be interested in knowing for what reason crashsite thinks that it is acceptable to learn R = V/I and not V/I multiplied by CF. I would like to know if anything besides perjorative language supports crashsite in this instance.
    Last edited by jasonbe; 13th July 2009 at 04:07 AM.
    She 'tis not there.

  15. #270
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    Quote Originally Posted by tcmtech View Post
    I think hes doing rather well being you keep giving him the attention! Direct attention or not, he is still hanging in there thanks to you!

    Crashsite 0
    Jasonbe 1


    I am almost half tempted to give jasonbe positive rep points just for playing you guys so very well!

    As inept as he may look at electronics and electrical theory he obviously knows how to play this game and he is playing it very very well!
    This may be risky, but I am tempted to ask you, as long as you are playing along - why is it likely that the sites that I have found describe the resistance correction factor - if that is in fact what CF stands for, as a function of only temperature and not probe spacing.
    She 'tis not there.

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