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| Math and Physics Discuss the complex nature of mathmatics and physics relating to electronic circuitry. |
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| Hey, I am a bit stumped on a text book question. I've attached the diagram to help. The questions states: Two circuits shown below are in identical black boxes with ONLY their terminals accessible from outside the box. How could you determine which box contains the Norton equivalent? What I think: Since Rnorton = RThevenin, we cannot find out by shutting of the current and voltage sources (I.E current source becomes open circuit / voltage source is short circuit) and measuring the resistance since Rnorton = RThevenin... I believe the answer is that we cannot determine one from the other since this is exactly the theorem... both circuits are equivalent to any device we place on the exposed nodes. Does this sound correct? Thanks!
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JimB
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| OK Thank you JimB
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| Norton involve current while thevenin theorem involve voltage..correct me if wrong | |
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