hello guys

This is my question


Find three consecutive odd integers such that 3 times their sum is 5 more than 8 times the middle one

 

you're kidding, right?

this the level of math at your college?

 

Homework, eh?

First you write down what you know, ie the question in form of math notation:

For integers, a,b and c, where a<b<c, and (a+1) = mod 2, (b+1) = mod2, (c+1) = mod2. Solve for a,b,c, when 3(a+b+c) = 5 + 8b.

Alternatively, if you read the question, you're not meant to calculate the answer, just find a,b,c so that the statement is true. For example, is it true for a=1, b=2, c=3?

 

hello guy

what's up man?

I haven't told you that the question is from my book

I've written it for enjoying

that's all
I hope to understand me

see ya

 

good for you

you're all right
but in my opinion if you take a look at the question you'll see that
three odd intergers


thanks again

 

Whops, my bad. The maths statement still holds ( x + 1 = mod 2, gives x an odd number). a, b, and c for values 1, 3, and 5, respectively.

 

I saw that the statement is true for a=3, b=5, c=7. But that was before I realised it the statement is 3(a+b+c)=8b-5, and not 3(a+b+c)=8b+5...

 

It is too easy to be a engineering collage level problem. As a rule I get such things wrong so let me give it a try. If I am wrong I am sure there will be no shortage of people with the right answer.

Find three consecutive odd integers such that 3 times their sum is 5 more than 8 times the middle one

The queston asks for three consecutive odd integers,
I would thake this to be numbers like
x, x+2, x+4 where x is odd.


(3 * (X + (x+2) + (x+4) ) ) -5 = ((X + 2) * 8)
3x + 3x + 6 + 3x + 12 = 8x + 16 + 5
x + 18 = 21
x = 3

check
3 * (3 + (3 +2) + (3+4) ) = ((3 + 2) * 8) + 5
3 * (3 + (5) + (7) ) = ((5) * 8) + 5
3 * (15 ) = (40) + 5
45 = 45

so the numbers are 3, 5, and 7

 

That is correct, apart from it is 3(a+b+c)+5=8b not 3(a+b+c)=8b+5.

 

no, 3(a+b+c)=8b+5 is correct.

the problem stated that 3 times the sum is 5 more than 8b.

3(a+b+c)+5=8b
would translate into 8b is 5 more than 3 times the sum.

 

Ah. Right you are..

 

As always I complicate things, congruent modulo was not the way to go. (However, I conjecture that it would give you all solutions to the problem if they exist...)

 

Thanks guys for intersting


remark : this isn't from engineering maths .it's just for enjoying