Circuit Analysis ( very urgent help ) - Electronic Circuits Projects Diagrams Free

kingcross · 26th September 2007, 01:27 PM

fb30e41f9a1318c450c1339d47b53157.jpg

please can someone help me solve this problem ( i attached the picture)

Question:- Use source transformation to determine the current and power in the 8-Ω resistor.

double click the attached diagram ( mistake on the diagram instead of using 20 V please use 15V) .....thanks

**Nigel Goodwin** · 26th September 2007, 02:10 PM

Perhaps you should do your own school work?.

ljcox · 27th September 2007, 10:12 PM

I suggest that you convert the 3A source and 10 Ohm resistor into the Thevenin equivalent.

Then find the Thevenin equivalent of the 15 Volt, 3 Ohm and 6 Ohm section.

The problem then becomes a simple series circuit.

engineers feel · 23rd October 2007, 09:15 PM

hello guy
the first step if you want to find
the current which cross the 8 ohm resistanse
you've to convert the current source with 10 ohm resistanse
to the voltge source
then as we kenw Is = 3 A of the voltage source
also 3 A
also the resistanses 10 ohm and 8 ohm in series
means they have the same currnet
then we've now I which equal to 3 A
and R which equal to 8 ohm
now we can get the power from this law
P = I^2 * R
P= 9 * 8 = 72 W

with best wishes

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26th September 2007, 01:27 PM	(permalink)
kingcross	Circuit Analysis ( very urgent help ) fb30e41f9a1318c450c1339d47b53157.jpg please can someone help me solve this problem ( i attached the picture) Question:- Use source transformation to determine the current and power in the 8-Ω resistor. double click the attached diagram ( mistake on the diagram instead of using 20 V please use 15V) .....thanks Last edited by kingcross; 26th September 2007 at 01:34 PM.

26th September 2007, 02:10 PM	(permalink)
Nigel Goodwin	Perhaps you should do your own school work?. __________________ PIC programmer software, and PIC Tutorials at: http://www.winpicprog.co.uk

27th September 2007, 10:12 PM	(permalink)
ljcox	I suggest that you convert the 3A source and 10 Ohm resistor into the Thevenin equivalent. Then find the Thevenin equivalent of the 15 Volt, 3 Ohm and 6 Ohm section. The problem then becomes a simple series circuit. __________________ Len

23rd October 2007, 09:15 PM	(permalink)
engineers feel	hello guy the first step if you want to find the current which cross the 8 ohm resistanse you've to convert the current source with 10 ohm resistanse to the voltge source then as we kenw Is = 3 A of the voltage source also 3 A also the resistanses 10 ohm and 8 ohm in series means they have the same currnet then we've now I which equal to 3 A and R which equal to 8 ohm now we can get the power from this law P = I^2 * R P= 9 * 8 = 72 W with best wishes