Latex Math Equations - Page 2 - Electronic Circuits Projects Diagrams Free

Stronghold_2 · 11th March 2007, 05:47 AM

Quote:

Originally Posted by Hero999

Please post a picture of the formula you want; use an easy to use program such as MS Equation for Word or OpenOffice Math.

I tried Hero999, but it would not upload. Anyways, sorry for the trouble.

Factorise:

(2 a square b square + 2 b square c square + 2 a square c square - a raised to the power of 4 - b raised to the power of 4 - c raised to the power of 4) / 16. The whole expression is under root.

Sorry, because the sum is in words.

Hero999 · 11th March 2007, 12:01 PM

For some reason the Latex on this form requires an variable/number followed by an equals sign.

For example, you can have:
$f_0 = \frac{1}{2 \pi sqrt{LC}}$
or:
$81 \times 10^6 = \frac{1}{2 \pi sqrt{82 \times 10^{-9} \times 47 \times 10^{-12}}}$
But you can't have:
$\frac{1}{2 \pi sqrt{LC}}$
or even something simple like:
$a+b$

I suppose a + b doesn't make much sense on its own.

Stronghold_2 · 11th March 2007, 03:36 PM

Quote:

Originally Posted by Hero999

For some reason the Latex on this form requires an variable/number followed by an equals sign.

For example, you can have:
$f_0 = \frac{1}{2 \pi sqrt{LC}}$
or:
$81 \times 10^6 = \frac{1}{2 \pi sqrt{82 \times 10^{-9} \times 47 \times 10^{-12}}}$
But you can't have:
$\frac{1}{2 \pi sqrt{LC}}$
or even something simple like:
$a+b$

I suppose a + b doesn't make much sense on its own.

I do not not understand what you express. However, that is beside the point. Could you please help my with me problem. I do not seem to get it.

Hero999 · 11th March 2007, 06:10 PM

I meant that Latex on this forum won't let you have:
a + b

you need to have:
c = a + b

This means that what you want to do won't work unless you have an = sign somewhere in-between some numbers or variables.

43617373 · 19th April 2008, 10:15 PM

$\lim_{h\to\0} \left( \frac{f(x+h)-f(x)}{h}\right)$

$P = F_{{||}}v$

$m_{{1}}v_{{1}} = m_{{1}}v_{{2}} + m_{{2}}v_{{3}}$

$z = {{{{{{{x^y}^a}^}^c}^}^}^d}$

Edit: thanks eng1

eng1 · 20th April 2008, 08:14 AM

Quote:

Originally Posted by 43617373

Is there any way to make power towers to work? putting in x^y^2 gives x^y2?

Like this? $b = x^{y^2}$

Use curly brackets to surrond expressions, like y^2.

Hero999 · 22nd August 2008, 12:04 AM

Accurate formula for calculating filter capacitor size on a linear regulator.

$C = \frac{I}{V_R} \times \left(\frac{1}{4f} + \frac{arcsin{\left(\frac{V_{IN}-V_R}{V_{IN}} \right)}}{2\pi f} \right)\\ C=\text{Minimum capacitance required}\\ V_R= \text{Maximum ripple}\\ V_{IN}= \text{Input voltage, excluding diode losses}\\ I=\text{Current drawn by regulator}\\ f= \text{Frequency}\\ $

Willbe · 22nd August 2008, 10:19 PM

Quote:

Originally Posted by Stronghold_2

Factorise:
2 a squared x b squared = A etc?
+ 2 b square c square = B
+ 2 a square c square = C
- a raised to the power of 4 = D
- b raised to the power of 4 = E
- c raised to the power of 4) = F
/ 16.
The whole expression is under root.

In American English, do you mean
X = [(A+B+C-D-E-F)/16]^0.5, so if A = 6, B= 5, C = 4 and so on, then X = 0.75?

and B, for example, = 2(b^2)(c^2), so if b = 2 and c = 3, then B = 72?

so I should come up with a general equation that solves for a, b and c?

If that's what you mean, I'll give it a try, but if I can't solve it in 10 pages I will quit.
:-)

Hero999 · 23rd August 2008, 03:08 PM

Whay are you responding to a post made over a year ago?

Aslo this thread is about the Latex feature of this forum, not maths help.

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11th March 2007, 12:01 PM	#17
Hero999	For some reason the Latex on this form requires an variable/number followed by an equals sign. For example, you can have: $f_0 = \frac{1}{2 \pi sqrt{LC}}$ or: $81 \times 10^6 = \frac{1}{2 \pi sqrt{82 \times 10^{-9} \times 47 \times 10^{-12}}}$ But you can't have: $\frac{1}{2 \pi sqrt{LC}}$ or even something simple like: $a+b$ I suppose a + b doesn't make much sense on its own. __________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer. Last edited by ElectroMaster; 12th October 2007 at 04:01 PM.

11th March 2007, 06:10 PM	#19
Hero999	I meant that Latex on this forum won't let you have: a + b you need to have: c = a + b This means that what you want to do won't work unless you have an = sign somewhere in-between some numbers or variables. __________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer.

19th April 2008, 10:15 PM	#20
43617373	$\lim_{h\to\0} \left( \frac{f(x+h)-f(x)}{h}\right)$ $P = F_{{\|\|}}v$ $m_{{1}}v_{{1}} = m_{{1}}v_{{2}} + m_{{2}}v_{{3}}$ $z = {{{{{{{x^y}^a}^}^c}^}^}^d}$ Edit: thanks eng1 __________________ Mechanical Engineers make weapons. Civil Engineers make targets. Last edited by 43617373; 20th April 2008 at 06:14 PM.

22nd August 2008, 12:04 AM	#22
Hero999	Accurate formula for calculating filter capacitor size on a linear regulator. $C = \frac{I}{V_R} \times \left(\frac{1}{4f} + \frac{arcsin{\left(\frac{V_{IN}-V_R}{V_{IN}} \right)}}{2\pi f} \right)\\<br /> C=\text{Minimum capacitance required}\\<br /> V_R= \text{Maximum ripple}\\<br /> V_{IN}= \text{Input voltage, excluding diode losses}\\<br /> I=\text{Current drawn by regulator}\\<br /> f= \text{Frequency}\\<br />$ __________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer.

23rd August 2008, 03:08 PM	#24
Hero999	Whay are you responding to a post made over a year ago? Aslo this thread is about the Latex feature of this forum, not maths help. __________________ I do not answer private messages asking for help because no one else can: benefit from advice I may give or correct me if I'm wrong. Please ask on the open forum if you have a question and I'll be happy to help, if I know the answer.