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| | #16 |
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audioguru,Thanks ,never knew of a "current regulator" great,Thanks. Sooo now ha ha ha ,,,,I just have to look for aaaaaa either a 3.5 or for 2 a 6 or a 10.5 for 3 of these. lol. Ok so dose any one have a cir. that would light 3 of these from a 12dc auto battary?Or is their one on the net. Thanks Guys.I do plumbing,heating,remodeling, ect, not making cir...oh well.Im trying ,If I had a cir. to follow no problem then I could make it. Thanks again guys. Johnny | |
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| | #17 |
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I think I found something that might work for lighting the 3 leds .what do you think. LM317 Current Calculator - Electric Circuit tks Johnny | |
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| | #18 |
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The LM317 articles are not correct. They forgot to say that the LM317 needs at least 2V plus the 1.2V for the current-setting resistor. Then the total minimum voltage needed is 3.2V for the current regulator. You want three LEDs in series that need at most 3.7V each which is 11.1V plus 3.2V for the current regulator. So you need a power supply that is a minimum of 14.3V which means a car battery will not work. Use the LM317 with two LEDs in series.
__________________ Uncle $crooge | |
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| | #19 | |
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What will happen to the 2.7V LED? Will it burn or will just have stronger illumination? Thanks. Last edited by alphacat; 30th October 2009 at 10:16 PM. | ||
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| | #20 |
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1 out of 1 members found this post helpful.
Depends on the driving voltage. Assuming 5 volts the lower voltage LED will get 10ma more current. It'll be really bright, and probably not last nearly as long. The higher the driving voltage the bigger the resistor you'll use is which makes it closer to an ideal current source, so the over current will be less. Moving to a 10 volt supply and a properly valued resistor for the higher LED will give you only 3ma more current for the second led
__________________ "Because I be what I be. I would tell you what you want to know if I could, mum, but I be a cat, and no cat anywhere ever gave anyone a straight answer, har har." Last edited by Sceadwian; 30th October 2009 at 11:50 PM. | |
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| | #21 |
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Went and picked up a LM317T. And I guess by what this says I need a 9 ohm resistor.for the 2 leds.Is that correct ? and to light 3 in series I would need to use a LM338T because that could take up to 5 amp. I didn't figure out the resistor for the LM338T yet. Tks Johnny Thought that I would be able to find this SMALL cir. on the net some were.oh well | |
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| | #22 | |
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You and we do not know if your LEDs are 2.7V or 3.7V or in between. If they are 2.7V then three in series need at least 8.1V plus 3.2V for the current-regulator circuit. Use Ohm's Law to calculate their current or to calculate the value for their current-limiting resistor. If your LEDs are actually 3.7V each then their total is 11.1V and they still need at least 3.2V for a current regulator circuit. Do you have at least 14.3V? If your LEDs are in parallel then show your schematic. 5A is a lot of current. What are you doing with it? Burning out LEDs?
__________________ Uncle $crooge | ||
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| | #23 |
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audio,I bought 3 of these LED and would like to run 2 in seires. off a 12dc car battary.here are the spec. 3W power consumption Copper base Voltage Input: 3.0V~3.27V Current: 700mA Brightness: 80 lumens (manufacturer rated) Color Temperature: 6700K white Size: 0.94 in x 0.47 in x 0.24 in Tks Johnny | |
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| | #24 | |
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You should use Name-Brand LEDs that have guaranteed detailed datasheet spec's. Why do people buy cheap junk?
__________________ Uncle $crooge | ||
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| | #25 |
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I see some 'smoked' LED's in his future. The best way to drive these high power LED from a battery is with a switching power supply that produces constant current. If you do it the simple way with dropping resistors then keep at least 25-30% overhead voltage drop across current limiting resistor. This will be painful as the resistors will generate significant heat. Also don't forget the LED's need their own heat sink. Last edited by RCinFLA; 31st October 2009 at 04:34 AM. | |
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| | #26 |
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I didn't think that a small simple cir. would be hard for someone that knew electronics. At what I use to do, I Never would say ,,It cant be done,I never gave up,and I always figured it out.I was just looking on the net and they make flash lights with 3 watt leds,If the led drew 3 volts, and a car battary usually is 12 to 14 vdc, I cant see why I couldn't put 5 in seires that would be 15v.Sure the brightness would go up or down "alittle" but I dont care if these are just for when the power goes out.Or just run 3 volt battaries.Or get the older type lead acid battary and TAP into the battary just to get 3 volts.I still say that someone on this whole internet would have a cir. for these 1-2-3 watt leds that would run on a 12volt car battary.I only have 3 right now,but if I did have 5 I would try them in seires and see what happens. Tks Johnny Still looking. | |
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| | #27 |
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I know this is a little complicated but this is what is inside LED flashlight bulbs. It will take a voltage and boost it up and regulate the current. The LED voltage must be higher than the battery voltage. It will keep the current constant untill the battery drops down to 3 volts. http://focus.ti.com/lit/ds/symlink/tps61160.pdf I have used many different types of LED drivers. Some work down to 0.6 volts. There are some "buck down" parts but I usually use "boost up" type. 1 to 8 volts in. http://www.diodes.com/datasheets/ZXSC310.pdf http://cache.national.com/ds/LM/LM3410.pdf hope this helps | |
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| | #28 |
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ronsimpson-I know that I brought up a flash light,.but All im trying to do is run these leds off of a 12vdc car deep cycle battery when the power goes out.I dont think that it is a big deal./I fool around eletronic's just a bit,but electrical I can do pretty well.To build a cir. I don't do that.That isn't my trade.ALL I asked from those that do this stuff is a Small cir.[which I know is very simple]. oh well. I;ll keep looking and trying. also I can just buy a car tail light with these leds in it, lol ..see how easy it is. But thanks for the reply. TKS Johnny. | |
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| | #29 |
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hi. m a newbie...... i wanted to light an led with 1W, 350mA.... I used a 20V derived from mains.... using 7805 I obtained a constant current source.. gave 20V i/p to 7805, betn o/p n common terminal of IC it gives 5V. across those two terminals i connected 13ohm to get 350mAs... the led is connected bet gnd n common of 7805.... i think this may help u...... bt u need to take care of ic as it gets heated much..... if u use this hope this helps u Last edited by bublee; 31st October 2009 at 01:31 PM. | |
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| | #30 | |
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They cannot make LEDs with a precise voltage like a resistive light bulb so each LED has a different voltage (2.7V to 3.7V). Since an LED is a diode then its current changes a lot if a varying voltage is fed to it. The current will be way too high or will be nothing. Therefore you must limit the current or regulate the current.
__________________ Uncle $crooge | ||
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