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Hello, I'm trying to verify that I correctly calculated the power in R5 shown in the circuit below. ![]() I first determined that the voltage over R5 is 4.91 v. Then I calculated power as P = (V^2)/R5 = 4.3 mW. I would greatly appreciate it if anyone could verify my calculations. Thanks! | |
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| | #2 |
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Show us your calculations........
__________________ Eccentric millionaire financed by 'er indoors | |
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R5 isnt in parallel with R3/R4......See your third line
__________________ Eccentric millionaire financed by 'er indoors | |
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Calc the value of R3 in parallel with R4 (514.29 ohms)....add R2 to that ( 144.29) , then calc that result in parallel with R5...(950.14)...call that Rz Add that to R1... Calc the current Iw thru R1+Rz... then Pdiss in R5 = Iw squared*R5
__________________ Eccentric millionaire financed by 'er indoors | |
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| | #7 |
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Why don't you use mesh analysis? you do the three meshes find the current thru R5, and you're done, it will be very fast if you use a graphing calculator.
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| I'm afraid that I haven't studied mesh analysis at all. But I'll look into that; thanks.
Last edited by Emil09; 29th October 2009 at 08:51 PM. | |
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| | #9 |
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Actually, what I'm really trying to verify is the following: ![]() for the circuit I originally posted. Thank you. | |
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deleted my answer
__________________ Eccentric millionaire financed by 'er indoors Last edited by Chippie; 29th October 2009 at 09:12 PM. | |
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| | #11 |
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1 out of 1 members found this post helpful.
As I see it, it's good, you'll get a the result, as long as you don't make a mistake with the numbers.
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| | #12 |
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Thanks. I'm studying for an exam and this is one of the things that was causing some confusion for me.
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| | #13 |
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As you see, there's a bunch of people here that can help you, hope you do it good.
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| calculating, circuit, power, seriesparallel |
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