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Thread: Math Help

  1. #1
    shermaine Newbie
    Join Date
    Jul 2003
    Posts
    547

    Math Help

    May i know how to solve this cot equation, i cant get the final answer if i will to use 1/tan

    -j75 x cot [ 2x 3.142/30] = -j 352 ohm
    Anyone can advise me?Thanks.


  2. #2
    Electronworks Newbie
    Join Date
    Aug 2009
    Posts
    86

    What variable are you looking to solve for? I cannot see one
    Bill Naylor
    www.electronworks.co.uk
    Electronics Design Consultancy

  3. #3
    Electronworks Newbie
    Join Date
    Aug 2009
    Posts
    86

    Here goes... You need to be working in radians:

    Assume 3.142 = pi (this will give you a more precise result)

    2pi/30 = 0.209

    tan 0.209 = 0.212.

    1/tan = cot = 1/0.212 = 4.705

    j75 x 4.705 = j352.8

    I am trying to relate this to something electronic, but cannot.

    Is this an equation related to a complex impedance (capacitive if we are talking -j)

    Please advise

    Thanks
    Bill Naylor
    www.electronworks.co.uk
    Electronics Design Consultancy

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