Ideal suppliers and Shorting - Electronic Circuits Projects Diagrams Free

Electronman · 3rd November 2009, 01:36 AM

an ideal voltage source has an internal resistance of zero. this means that it can deliver any current while its voltage is not affected, right? If so then what will happen if I put a zero resistor to its terminals or short its terminals?
If I put a voltmeter across a such supplier then what what do I''ll read when I short the supplier?

THANKS

Warpspeed · 3rd November 2009, 02:26 AM

You will still read the correct output voltage.

The current will be infinite.
Not just thousands of millions of amps but truly INFINITE.

Sceadwian · 3rd November 2009, 02:31 AM

An ideal voltage source is just that, mathematically ideal, none such can exist in the real world.

Karkas · 3rd November 2009, 02:36 AM

The circuit theory says that you can't short circuit an ideal voltage current, because as you said its internal resistance is "0". And you can not either left in open circuit an ideal current source because its internal resistance is infinite.

Electronman · 3rd November 2009, 02:51 AM

Quote:

Originally Posted by Karkas

The circuit theory says that you can't short circuit an ideal voltage current, because as you said its internal resistance is "0". And you can not either left in open circuit an ideal current source because its internal resistance is infinite.

Thanks for all inputs.

Can somebody explain it mathmatecaly to me? When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??!

Karkas · 3rd November 2009, 02:58 AM

Quote:

Originally Posted by Electronman

Thanks for all inputs.

Can somebody explain it mathmatecaly to me?
If you make the calculus you will have an infinite current, and that mathematically is right, but the circuit theory says that you can't short circuit that source.

When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??!
It couldn't, because no current will flow through a load that is bigger than "0" when there's a short circuit.

is there any disagreement or confusion?

Warpspeed · 3rd November 2009, 03:33 AM

It can feed as many additional loads that you have, at full voltage too.

Simply because the current source is infinite, so it can never be overloaded.

Electronman · 3rd November 2009, 04:00 AM

Quote:

Originally Posted by Warpspeed

It can feed as many additional loads that you have, at full voltage too.

Simply because the current source is infinite, so it can never be overloaded.

But I Can not understand it Mathematically?!

Warpspeed · 3rd November 2009, 04:16 AM

Infinity is so very large, is beyond understanding.

That is the whole point.

Noggin · 3rd November 2009, 09:40 AM

Quote:

Originally Posted by Electronman

Thanks for all inputs.

Can somebody explain it mathmatecaly to me? When you short a voltage source then how does it feeds another load which is parallel to that shorted pin??!

If you short a non-ideal voltage source then it will NOT power a load parallel to the short.

Electronman · 3rd November 2009, 09:51 AM

Quote:

Originally Posted by Noggin

If you short a non-ideal voltage source then it will NOT power a load parallel to the short.

I am talking about an IDEAL one!

Warpspeed · 3rd November 2009, 10:00 AM

Yup, an IDEAL voltage source, with infinitely more power than all the Galaxies in the cosmos combined.

Sceadwian · 4th November 2009, 02:47 AM

Voltage source - Wikipedia, the free encyclopedia
What don't you understand?

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3rd November 2009, 01:36 AM	#1
Electronman	Ideal suppliers and Shorting an ideal voltage source has an internal resistance of zero. this means that it can deliver any current while its voltage is not affected, right? If so then what will happen if I put a zero resistor to its terminals or short its terminals? If I put a voltmeter across a such supplier then what what do I''ll read when I short the supplier? THANKS

3rd November 2009, 02:26 AM	#2
Warpspeed	You will still read the correct output voltage. The current will be infinite. Not just thousands of millions of amps but truly INFINITE.

3rd November 2009, 02:31 AM	#3
Sceadwian	An ideal voltage source is just that, mathematically ideal, none such can exist in the real world. __________________ "Because I be what I be. I would tell you what you want to know if I could, mum, but I be a cat, and no cat anywhere ever gave anyone a straight answer, har har." Last edited by Sceadwian; 3rd November 2009 at 02:32 AM.

3rd November 2009, 02:36 AM	#4
Karkas	The circuit theory says that you can't short circuit an ideal voltage current, because as you said its internal resistance is "0". And you can not either left in open circuit an ideal current source because its internal resistance is infinite. __________________ "A person who never made a mistake never tried anything new" Albert Einstein

3rd November 2009, 03:33 AM	#7
Warpspeed	It can feed as many additional loads that you have, at full voltage too. Simply because the current source is infinite, so it can never be overloaded.

3rd November 2009, 04:16 AM	#9
Warpspeed	Infinity is so very large, is beyond understanding. That is the whole point.

3rd November 2009, 10:00 AM	#12
Warpspeed	Yup, an IDEAL voltage source, with infinitely more power than all the Galaxies in the cosmos combined.

4th November 2009, 02:47 AM	#13
Sceadwian	Voltage source - Wikipedia, the free encyclopedia What don't you understand? __________________ "Because I be what I be. I would tell you what you want to know if I could, mum, but I be a cat, and no cat anywhere ever gave anyone a straight answer, har har."