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completely switching off a mosfet completely switching off a mosfet
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Old 6th October 2009, 08:37 PM   #16
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Old 7th October 2009, 06:17 PM   #17
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Originally Posted by BrownOut View Post
I think the OP's question still hasn't been answered, so I'll give it a try. The answer is yes, the IC is providing a path to discharge the FET gate. The question then becomes, does the IC sinc enough current to turn the FET off quickly??? I could go through the datasheet and come up with an answer, but this is your design; your responsibility. If it turns out that the current isn't sufficient, then you'll have to try some of the ideas for increasing the drive. Good luck.
I think you missed the point a bit, I don't have a problem with the current requirement, but if I need to bring a fets gate to VCC (also the source voltage) then its theoretically impossible as any device controlling the gate will have a voltage drop.
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Old 7th October 2009, 06:34 PM   #18
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I think you missed the point a bit, I don't have a problem with the current requirement, but if I need to bring a fets gate to VCC (also the source voltage) then its theoretically impossible as any device controlling the gate will have a voltage drop.
You're right. There are two threads within a single thread. I was confused thinking that you and kinarfi were collaborating on a project. Is your question still unanswred? I thought AG gave a pretty good answer. It it possible to just switch off the field you are trying to drive, so this isn't an issue?
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Old 7th October 2009, 06:40 PM   #19
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There is only a voltage drop when you are passing current. Once the gate is "discharged" the voltage will settle and be the same as the source voltage.
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Old 7th October 2009, 11:42 PM   #20
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Reply deleted - My Bad - I had replied to a hijack and my reply was irrelevant to the original question.
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Last edited by mneary; 7th October 2009 at 11:54 PM.
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Old 7th October 2009, 11:46 PM   #21
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I hate it when people hijack threads. I'm always giving confused answers.
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