High Pass filter - Electronic Circuits Projects Diagrams Free

Hraesvelg · 25th March 2004, 12:02 AM

If I have values for R, C, and I know a function for the input voltage with respect to time how do I plot a graph with the output voltage?

Russlk · 25th March 2004, 04:53 AM

It has been many years since I had to do math, but I think this is correct:

Painandsuffering · 25th March 2004, 08:32 PM

Quote:

Originally Posted by Russlk

It has been many years since I had to do math, but I think this is correct:

Nice try at the math where some of it might be right z=square root of Rsquared+ XCsquared. xc= 2*pi*f*c then reciprocate that and you get xc.

Russlk · 25th March 2004, 10:42 PM

You are SO right! I have corrected my post, thanks.

Hraesvelg · 26th March 2004, 02:44 AM

Vout=Vin*(1/sqrt(1+(1/(2*Pi*R*C))^2))

For High Pass filter

Roff · 26th March 2004, 03:33 AM

In the time domain (which is what you asked for),

Vout(t)=Vin(t)*(1/(R*C))e^(-t/(R*C))

Where Vout(t), Vin(t) denotes that they are functions of time.

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25th March 2004, 12:02 AM	(permalink)
Hraesvelg	High Pass filter If I have values for R, C, and I know a function for the input voltage with respect to time how do I plot a graph with the output voltage?

25th March 2004, 10:42 PM	(permalink)
Russlk	You are SO right! I have corrected my post, thanks. __________________ see my website: www.geocities.com/russlk

26th March 2004, 02:44 AM	(permalink)
Hraesvelg	Vout=Vin(1/sqrt(1+(1/(2PiRC))^2)) For High Pass filter

26th March 2004, 03:33 AM	(permalink)
Roff	In the time domain (which is what you asked for), Vout(t)=Vin(t)(1/(RC))e^(-t/(R*C)) Where Vout(t), Vin(t) denotes that they are functions of time.