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Hi
I am trying to solve the same circuit by using thevenin's , norton and superposition theorem. Can any body help me in solving and understanding the circuit. Thanks |
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Thevenin Theorem and superposition theorem methods attached.
Thevenin Cut the circuit at the red lines. Calculate the Thevenin voltages and resistances. The Thevenin voltage at a is the voltage that would be measured between a and 0 with a voltmeter, and the Thevenin resistance is the resistance that would be measured between a and 0 with an Ohmmeter with the voltage source replaced by a short circuit. The same applies to the right hand side. Now connect the 12 Ohm resistor between the two Thevenin resistors. Then calculate the current, and hence the voltages at a and b with respect to 0. Superposition Replace one voltage source with a short circuit, and calculate the voltages at a and b with respect to 0 and call them Va1 and Vb1. This can be done using Ohm's Laws, Kirchoff's Laws or Thevenin's Theorem. Now restore the voltage source and replace the other one with a short circuit. Calculate the voltages at a and b with respect to 0 and call them Va2 and Vb2. The voltages at a and b with respect to 0 are now the sum of these voltages. Va = Va1 + Va2, and Vb = Vb1 + Vb2. |
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Here is the solution using the Norten Theorem
Len |
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Thanks to you all friends for the response. Sorry that I did not give you one more information. In the above circuit, I wanted to find current in 8 ohms resistor and not 10 ohms. Sorry once again.
The answer should be some where around 0.24 A , but iam not getting the steps to do that. Could you please help me once again Thanks |
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Len |
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