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Old 24th January 2003, 05:22 AM   (permalink)
Default variable resistor

on standard potentiometers, as well as the little blue surface mount version, there are 3 pins. on the pinout sheets they say "wiper" for the third pin. I know the wiper is the little physical thing that spins around to adjust the resistance, however, where does this pin go out to on the circuit?
ex

|(1) |(2)
|(3)

this is what the bottom of my little blue guy looks like.

i would imagine 1 and 2 are like the normal leads on a nonvariable resistor, but what do i do with pin 3 (wiper)?

thanks
david
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Old 24th January 2003, 05:31 AM   (permalink)
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Connect the wiper to either pin 1 or pin 3 to get a 2-wire variable resistor. To make a variable potential-divider, take the output between wiper and 3-pin and connect the input to pins 1 and 3 (This connection is used in audio amplifiers for volume control).
See picture below:
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File Type: gif POT.gif (1.1 KB, 404 views)
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Old 24th January 2003, 02:47 PM   (permalink)
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thanks man!
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