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Old 25th August 2008, 10:56 AM   (permalink)
Talking Diode uusmoothed output

can a typical Diode output be transformed? If yeah, how would it differ from complete AC output in ref to transformation features?



Muhammad89
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Old 25th August 2008, 05:35 PM   (permalink)
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Transformers are designed to use AC sine-waves.
A rectified sine-wave is not a sine-wave anymore and it is not AC since it is a fluctuating DC.
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Old 25th August 2008, 05:42 PM   (permalink)
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Originally Posted by Muhammad89 View Post
can a typical Diode output be transformed? If yeah, how would it differ from complete AC output in ref to transformation features?



Muhammad89
Transformed? Possible depending on one's definition. The pulsating DC output of rectifier diodes can be 'transformed' by way of additional capacitors to form voltage doubler/tripler/etc. circuits.

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Old 28th August 2008, 08:37 PM   (permalink)
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The pulsating DC output of rectifier diodes can be 'transformed' by way of additional capacitors to form voltage doubler/tripler/etc. circuits.
Technically correct, if the pulsating DC has a way of returning the current on the downward swing. Although the doubler, etc. doesn't care about the DC operating point, current must flow in both directions from the source.
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Old 28th August 2008, 10:38 PM   (permalink)
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Technically correct, if the pulsating DC has a way of returning the current on the downward swing. Although the doubler, etc. doesn't care about the DC operating point, current must flow in both directions from the source.
Makes no difference, a doubler etc. connects via a series capacitor, this makes the signal swing positive and negative around the centre.

But really we've never been clearly informed what the question was.
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Old 28th August 2008, 11:35 PM   (permalink)
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A doubler requires current flow in both directions. A pulsing DC from a rectifier can only supply current in one direction (usually positive). The diodes block the current flowing the other way. As you say, the center voltage doesn't matter. To drive the doubler's rectifiers, you need current flow in both directions.
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