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| Hello, I want to use 555 timer to generate a variable frequency waveform with a 50% duty cycle. Please tell me if this design makes sense. Basically, the idea is for capacitor (C1) to charge through Rc+RV and discharge via Rd + RV. Since Rv is a 10K POT, I should be able to vary the frequency by adjusting it without affecting the duty cycle. Does This make sence ? Thanks P.S. I apologies for the size of picture...(damn that scanner)
__________________ "The people who cast the votes don't decide an election, the people who count the votes do." -Joseph Stalin Last edited by Frosty_47; 9th April 2008 at 09:31 PM. | |
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| i have enclosed below the circuit diagram of 555 timer in astable mode... this circuit is good enough to generate a waveform with 50% duty cycle and above... however if u wih to have a waveform with a duty cycle less than 50%, you can use a small signal diode such as the 1N4148 and place it parallel to the resistor R2.... | |
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| T = 0.7 * (R1+2R2) * C1 where T is the time period of the waveform you desire to produce in seconds. T = Tm + Ts where Tm = output high during this time = 0.7 * (R1+R2) * C1 Ts = output low during this time = 0.7 * (R2) * C1 Duty Cycle = Tm / (Tm+Ts) = (R1+R2) / (R1+2R2) For 50% duty cycle Tm = Ts. | |
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I don't see how your design will provide a 50% duty. Please Xplain...
__________________ "The people who cast the votes don't decide an election, the people who count the votes do." -Joseph Stalin Last edited by Frosty_47; 9th April 2008 at 04:59 PM. | ||
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| Frosty, if the diode were ideal (zero forward voltage), that would work. However, when Rv is large, the drop across the diode is too low for it to conduct, so the resistor in parallel with it is still in the equation. If you want variable frequency with 50% duty cycle, use a CMOS 555 (because its output swings rail-to-rail) with this circuit. Keep the resistor value large, so the pin 3 output resistance is insignificant. The other way to do it, which yields even better results, is to use a variable-frequency 555 circuit with arbitrary duty cycle, then follow it with a toggle flip-flop (divide by 2). | |
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I would also do it this way, you are sure to get a 50/50 duty cycle throughout the 555 variable frequency range.
__________________ Eric "Good enough is Perfect" PIC tutorials: Gramo's: www.digital-diy.net/ Bill's: www.blueroomelectronics.com/ | ||
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| Thank you Roff for your circuit suggestion and explaining. If I use a 6K resistor in series with a 50K POT, and a 0.01uF Cap, I should be getting around 1275Hz-11904Hz (or 637.5Hz-5952Hz after flip flop). Are theese resistor values high enough? Thanks
__________________ "The people who cast the votes don't decide an election, the people who count the votes do." -Joseph Stalin | |
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74LS76/54LS76 should do the job...
__________________ "The people who cast the votes don't decide an election, the people who count the votes do." -Joseph Stalin Last edited by Frosty_47; 9th April 2008 at 08:58 PM. | ||
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| If you're using TTL, you don't need a CMOS 555, nor do you need the circuit in the link I posted (although it does have fewer parts). Most 74LS TTL is only guaranteed to operate over the range 4.75 to 5.25V. | |
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| When I use multisim to test this circuit it gives me slightly different output frequency than calculatted (I used virtual components in the circuit). The period of waveform I am getting on osciloscope: for 6k = 207.9uS = 4810Hz 56k = 1.6ms = 625Hz 5k = 168.0us = 5952.38Hz 55k = 1.5ms = 666.7Hz How come the frequencies in Multisim do not agree with the calculatted, even though I use Ideal components ? Basically I should use a 5k in series with 50K POT to achieve roughly 600Hz-6Khz. Is the reading in multisim accurate ?
__________________ "The people who cast the votes don't decide an election, the people who count the votes do." -Joseph Stalin Last edited by Frosty_47; 10th April 2008 at 12:57 AM. | |
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| You can try a 4027 or 4096 CMOS JK flip-flop to avoid voltage limits. | |
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